Compare x and y (define the answer codes): I. 17x^2 + 48x = 9 II. 13y^2 = 32y − 12 Choose: A) x > y B) x < y C) x = y D) Relationship cannot be determined

Difficulty: Medium

Correct Answer: x < y

Explanation:


Introduction / Context:
We compare solutions from two quadratic relations. If every possible x is strictly less than every possible y, we can conclude x < y. Compute the roots for both to compare their ranges.

Given Data / Assumptions:

  • I: 17x^2 + 48x − 9 = 0.
  • II: 13y^2 − 32y + 12 = 0.


Concept / Approach:
Use quadratic formula to get all roots. Compare the largest x to the smallest y; if the largest x is still less than the smallest y, then every x is less than every y.


Step-by-Step Solution:

I: Δ = 48^2 − 4*17*(−9) = 2304 + 612 = 2916 ⇒ √Δ = 54.x = [−48 ± 54]/(34) ⇒ x ∈ { (6/34) ≈ 0.17647, (−102/34) = −3 }.II: Δ = (−32)^2 − 4*13*12 = 1024 − 624 = 400 ⇒ √Δ = 20.y = [32 ± 20]/(26) ⇒ y ∈ { 52/26 = 2, 12/26 ≈ 0.46154 }.Largest x is ≈ 0.17647; smallest y is ≈ 0.46154. Therefore, even the largest x is less than the smallest y ⇒ x < y for all choices.


Verification / Alternative check:
Check all pairings: {−3, 0.17647} versus {0.46154, 2}; all comparisons show x < y.


Why Other Options Are Wrong:

  • x > y or x = y: Contradicted by numeric ranges.
  • Relationship cannot be determined: Not the case; strict separation exists.


Common Pitfalls:
Not identifying the smallest y and largest x correctly; mixing signs or miscomputing discriminants can flip conclusions.


Final Answer:

x < y

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