Reciprocal roots condition (standard form): For the quadratic ax^2 + bx + c = 0 with nonzero roots, the roots are reciprocals of each other if and only if:

Difficulty: Easy

Correct Answer: c = a

Explanation:


Introduction / Context:
If r and s are the roots of ax^2 + bx + c = 0, then r*s = c/a by Vieta. The roots are reciprocals of each other precisely when r*s = 1 and both are nonzero, which directly translates to c/a = 1 ⇒ c = a. This is a textbook criterion for reciprocal roots.

Given Data / Assumptions:

  • Quadratic: ax^2 + bx + c = 0.
  • Roots are real or complex but nonzero.


Concept / Approach:
Use the product of roots formula. The reciprocity condition requires the product to equal 1, hence c/a = 1.


Step-by-Step Solution:

Product of roots = c/a.Reciprocal condition: r*s = 1 ⇒ c/a = 1 ⇒ c = a.


Verification / Alternative check:
Consider transformed polynomial with roots 1/r and 1/s. Its monic form relates coefficients by swapping a and c, reinforcing the symmetry when c = a.


Why Other Options Are Wrong:

  • a = b or b = c: Do not constrain the product to be 1.
  • None of these: Incorrect; c = a is the correct and sufficient condition.


Common Pitfalls:
Overlooking the nonzero requirement (a root 0 breaks reciprocity) or confusing with the equal-roots discriminant condition.


Final Answer:

c = a

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