For a watershed with fair pasture cover, if potential infiltration s = 10 cm and storm rainfall P = 12 cm, what is the direct runoff depth Q?

Difficulty: Easy

Correct Answer: 2 cm

Explanation:


Introduction / Context:
Quick event-based runoff estimates often use simple abstractions where a potential infiltration depth s is subtracted from rainfall depth P to compute direct runoff Q. This is useful for rapid checks and teaching fundamentals before applying full SCS-CN or infiltration-capacity models.


Given Data / Assumptions:

  • Potential infiltration s = 10 cm.
  • Storm rainfall P = 12 cm.
  • Neglect other abstractions (interception, depression storage) for this simplified calculation.


Concept / Approach:
If rainfall does not exceed potential infiltration, no direct runoff occurs. If it exceeds s, the excess becomes runoff. Hence: Q = max(0, P − s). This linear model captures the threshold behavior simply and is commonly introduced in hydrology courses.


Step-by-Step Solution:

Compute excess rainfall: P − s = 12 − 10 = 2 cm.Since 12 > 10, runoff exists and equals the excess.Therefore, Q = 2 cm.


Verification / Alternative check:
While SCS-CN could give a slightly different value depending on Ia and S, the question clearly frames the simple potential-infiltration model, so the linear result stands.


Why Other Options Are Wrong:

  • 3 cm, 5 cm, 8 cm: Do not match P − s = 2 cm for the specified s and P under this model.


Common Pitfalls:

  • Accidentally using P/s or other ratios instead of the threshold subtraction.
  • Forgetting that runoff cannot be negative.


Final Answer:
2 cm

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