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If normal stresses due to longitudinal and transverse loads on a bar are σ1 and σ2 respectively, the normal component of the stress on an inclined plane θ° to the longitudinal load, is

σ1 sin θ x σ2 cos θ
σ1 sin θ2 + σ2 cos2 θ

Correct Answer: σ1 sin θ2 + σ2 cos2 θ

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