Difficulty: Easy
Correct Answer: Every horizontal plane across the depth (maximum at neutral axis)
Explanation:
Introduction / Context:
In strength of materials, transverse loading on beams induces both bending and shear. For rectangular sections, the distribution of shear stress through the depth is a classic result that every engineer should know when checking web shear and designing reinforcements or web thicknesses.
Given Data / Assumptions:
Concept / Approach:
The shear stress distribution in a rectangular section under transverse shear is parabolic:
tau(y) = (3/2) * (V / A) * (1 - (2y/h)^2)where y is measured from the neutral axis and h is the depth. The stress is zero at the extreme fibres (top and bottom) and maximum at the neutral axis. Therefore, shear acts on every horizontal plane, not just at a single fibre.
Step-by-Step Solution:
Verification / Alternative check:
Average shear V/A equals two-thirds of the maximum shear for a rectangle, consistent with the parabolic law (tau_max = 1.5 * V/A).
Why Other Options Are Wrong:
Common Pitfalls:
Assuming uniform shear stress; forgetting that design for web shear must consider maximum at the neutral axis.
Final Answer:
Every horizontal plane across the depth (maximum at neutral axis)
Discussion & Comments