Solid circular shaft in torsion — radial variation of shear stress In a solid circular shaft subjected to a torque (pure torsion), how does the shear stress vary from the centre to the outer surface?

Difficulty: Easy

Correct Answer: Zero at the centre and maximum at the circumference

Explanation:


Introduction / Context:
Torsion of circular shafts is a cornerstone topic in machine and structural design. Correctly recalling the shear stress distribution is essential for sizing shafts and checking combined stress states.



Given Data / Assumptions:

  • Solid circular shaft of radius R under torque T.
  • Material is homogeneous and linear-elastic; Saint-Venant torsion applies.


Concept / Approach:
For a solid circular shaft, the shear stress varies linearly with radius:
tau(r) = (T * r) / Jwhere J is the polar moment of inertia. Therefore, tau = 0 at r = 0 and tau = tau_max at r = R.



Step-by-Step Solution:

Write torsion formula: tau = T r / J.At r = 0 (shaft axis), tau = 0.At r = R (outer fibre), tau = T R / J (maximum value).


Verification / Alternative check:
The angle of twist formula theta = T L / (G J) also relies on J; using the linear tau–r law integrates to the correct torque–stress relationship.



Why Other Options Are Wrong:

  • Maximum at centre: contradicts tau = T r / J.
  • Uniform: only true for thin-walled tubes under special approximations, not solid shafts.
  • Maximum at mid-radius: incorrect; linear variation peaks at the surface.


Common Pitfalls:
Confusing solid and hollow shafts; misremembering that stress is linear (not parabolic) in torsion for circular shafts.



Final Answer:
Zero at the centre and maximum at the circumference

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