Thin cylindrical boiler — ratio of hoop (circumferential) stress to longitudinal stress For a thin-walled cylindrical boiler under internal pressure, what is the ratio of the tensile (normal) stress in the circumferential (hoop) direction to the tensile stress in the longitudinal (axial) direction?

Difficulty: Easy

Correct Answer: 2

Explanation:


Introduction / Context:
In thin pressure vessels, two principal membrane stresses arise: the circumferential (hoop) stress and the longitudinal (axial) stress. Correctly identifying their magnitudes is crucial for safe shell thickness design.



Given Data / Assumptions:

  • Thin-wall assumption: wall thickness t is small compared to diameter D.
  • Internal pressure p is uniform; end caps are integral.


Concept / Approach:
Classical thin-cylinder formulas:
sigma_hoop = p * D / (2 * t)sigma_longitudinal = p * D / (4 * t)Taking the ratio gives 2.



Step-by-Step Solution:

Write equilibrium of half-cylinder in the hoop direction to get sigma_hoop.Write equilibrium of the cylindrical shell end to get sigma_longitudinal.Compute ratio: (pD / 2t) / (pD / 4t) = 2.


Verification / Alternative check:
Dimensionally consistent; widely cited in pressure vessel design texts.



Why Other Options Are Wrong:

  • 4 or 3: overestimates; not supported by thin-wall equilibrium.
  • 1: would imply equal stresses, which is incorrect.
  • 1/2: reversed ratio.


Common Pitfalls:
Using diameter versus radius inconsistently; mixing thick-wall formulas with thin-wall assumptions.



Final Answer:
2

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