Difficulty: Medium
Correct Answer: exp(−(μ * x / R + k * x))
Explanation:
Introduction / Context:
In post-tensioned concrete, tendon force reduces from the jacking end due to curvature (friction proportional to μ times total angular change) and unintended wobble or misalignment (modeled by k per unit length). Estimating the remaining force at a distance x is necessary to verify stresses and ultimate capacity along the member.
Given Data / Assumptions:
Concept / Approach:
The standard friction-loss model yields the exponential decay expression: T(x) = T₀ * exp(−(μ * θ + k * x)), where θ is the total angular change between the jacking end and section at x. For constant radius, θ = x / R, giving T(x)/T₀ = exp(−(μ * x / R + k * x)).
Step-by-Step Solution:
Verification / Alternative check (if short method exists):
For straight tendon (R → ∞), term μ * x / R → 0, leaving T/T₀ = exp(−k x), matching the special case with wobble only.
Why Other Options Are Wrong:
Options A or B consider only one loss mechanism; D is a linear approximation, not used for design; E has sign error for the curvature term.
Common Pitfalls (misconceptions, mistakes):
Using degrees for θ without converting to radians; ignoring that k is per unit length; assuming μ effects vanish on small curvatures without checking magnitude.
Final Answer:
exp(−(μ * x / R + k * x))
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