Q: Polymer gasoline manufacture: In catalytic polymerization units that convert light olefins to higher-octane gasoline components, which catalyst system is commonly employed?

Introduction / Context: Catalytic polymerization (historical “polymer gasoline”) combines light olefins such as propylene and butylenes into higher molecular weight gasoline components. The process predates modern oligomerization/alkylation technologies and uses specific acid catalysts to drive carbon–carbon bond formation. Given Data / Assumptions: Feed: C3–C4 olefins from FCC or thermal cracking. Objective: produce high-octane gasoline blend stock. Catalyst options include acid and non-acid systems. Concept / Approach: A classic catalyst for polymerization to gasoline is phosphoric acid supported on kieselguhr (siliceous support). Strong solid acids promote olefin polymerization/oligomerization. Aluminium chloride is a Lewis acid for Friedel–Crafts reactions in different contexts; nickel is primarily for hydrogenation; vanadium pentoxide serves in oxidation (e.g., SO2→SO3), not olefin polymerization; an inert zeolite Y without an acid function would not be active for polymerization. Step-by-Step Solution: Match process class (olefin polymerization) with acid catalysis requirement.Identify the well-known catalyst: H3PO4 on kieselguhr.Exclude listed catalysts that do not fit the mechanism. Verification / Alternative check: Refinery process summaries list solid phosphoric acid (SPA) catalysts as standard for polymer gasoline/oligomer units, producing high-octane streams rich in branched components. Why Other Options Are Wrong: AlCl3: used in alkylation/acylation chemistry, corrosive and not the classic polymer gasoline catalyst.Nickel: hydrogenation, not polymerization.V2O5: oxidation catalyst.Zeolite Y (non-acid): insufficient acidity for polymerization. Common Pitfalls: Confusing polymerization with alkylation or hydrogenation; all three use different catalytic functionalities. Final Answer: phosphoric acid supported on kieselguhr

Q: Ignition quality reference scale (diesel): On the historical cetane number scale for compression-ignition fuels, the reference value assigned to alpha-methylnaphthalene is taken as what?

Introduction / Context: Cetane number quantifies diesel fuel ignition quality. The scale originally used two reference hydrocarbons: n-cetane (high ignition quality) and alpha-methylnaphthalene (poor ignition quality). Understanding the endpoints of this scale is foundational in fuel testing. Given Data / Assumptions: CFR engine test methods define cetane number. Original references: n-cetane (assigned 100) and alpha-methylnaphthalene (assigned 0). Modern practice often uses heptamethylnonane (isocetane) as a 15 reference, but the 0-point legacy still appears in exams. Concept / Approach: The conventional historical assignment places alpha-methylnaphthalene at the zero point due to its very poor auto-ignition tendency in CI engines, thereby setting the lower bound of the cetane scale. This provides a linear reference between poor and excellent ignition fuels for calibration and comparison. Step-by-Step Solution: Recall scale anchors: alpha-methylnaphthalene = 0; n-cetane = 100.Relate scale meaning: higher cetane number → shorter ignition delay.Select the zero assignment for alpha-methylnaphthalene. Verification / Alternative check: Standards literature notes the later substitution of isocetane (15) for handling reasons, but the original 0 assignment for alpha-methylnaphthalene remains the canonical teaching point. Why Other Options Are Wrong: 100: reserved for n-cetane, the high-quality reference fuel.50: arbitrary midpoint, not a reference assignment.Infinite: not meaningful in this scale.15: relates to isocetane, not alpha-methylnaphthalene. Common Pitfalls: Confusing the updated reference pair (isocetane 15) with the historical zero point; the question explicitly names alpha-methylnaphthalene. Final Answer: 0

Question 1

Flash point testing: for middle distillates such as diesel and kerosene that typically have flash points greater than 50°C, identify the standard apparatus used to determine flash point under closed-cup conditions.

Accepted Answer

Introduction / Context: Flash point is a key safety property indicating the lowest temperature at which a fuel emits sufficient vapour to ignite momentarily under test conditions. For middle distillates like kerosene and diesel—whose flash points are generally above 50°C—industry standards prescribe specific test apparatus and procedures to ensure reliable, comparable results. Given Data / Assumptions: Fuel: diesel or kerosene with flash point typically > 50°C. Testing environment: standardized closed-cup method. Objective: select the correct apparatus name. Concept / Approach: The Pensky-Martens closed-cup apparatus is widely used for measuring flash points of middle distillates and heavier oils because it minimizes vapour losses and better reflects storage and handling conditions. The Abel apparatus is commonly used for lower-flash, more volatile products. The Saybolt chromometer is not a flash point device; it measures colour (Saybolt colour scale) of light petroleum products. Step-by-Step Solution: Identify the fuel class and expected flash point (> 50°C).Recall that Pensky-Martens is the standard closed-cup method for such fuels.Select “Pensky-Martens apparatus.” Verification / Alternative check: Fuel standards (e.g., for diesel/kerosene) reference Pensky-Martens for specification compliance, ensuring consistency across laboratories. Why Other Options Are Wrong: Abel apparatus: oriented to lower-flash volatile products.Saybolt chromometer: measures colour, not flash point.None of these: incorrect because Pensky-Martens is correct. Common Pitfalls: Confusing open-cup and closed-cup methods; closed-cup generally gives lower flash points due to containment of vapours. Final Answer: Pensky-Martens apparatus

Question 2

Refining separation — dewaxing know-how: In the Barisol solvent dewaxing process used to lower the pour point of waxy distillates, which solvent system is employed as the characteristic dewaxing medium?

Accepted Answer

Introduction / Context: Dewaxing is a key refining step to improve low-temperature flow properties of middle distillates and lube base stocks. Several named processes exist, each defined by its solvent system and operating method. The Barisol process is a classic solvent dewaxing route historically highlighted in petroleum exam questions. Given Data / Assumptions: Objective: identify the solvent pair specific to the Barisol dewaxing process. Feed: waxy petroleum fractions requiring pour point reduction. Context: comparison against other common solvents (MEK/toluene, propane, furfural, hexane). Concept / Approach: Solvent dewaxing relies on selective dissolution and crystallization. A characteristic signature of the Barisol process is its use of benzol (benzene) together with ethylene dichloride as the mixed solvent. Other solvent systems correspond to different proprietary processes (e.g., MEK + toluene for modern solvent dewaxing, liquid propane for propane dewaxing; furfural is an extraction solvent for aromatics, not a dewaxing solvent). Step-by-Step Solution: Identify Barisol in refinery literature as a benzene + ethylene dichloride solvent system.Map other listed solvents to their typical processes: MEK (with toluene) for solvent dewaxing; propane for propane dewaxing; furfural for lube extraction; hexane as a generic paraffinic solvent but not the Barisol pair.Select the option matching the Barisol signature: benzol and ethylene dichloride. Verification / Alternative check: Cross-references of historical process names consistently tie “Barisol” to the benzene + ethylene dichloride mixture for promoting wax crystal formation and filtration at low temperatures. Why Other Options Are Wrong: Hexane: not the defining Barisol solvent.Furfural: an aromatics extraction solvent, not used for dewaxing.MEK: common in other dewaxing schemes but not Barisol’s hallmark.Propane: different (propane dewaxing) route. Common Pitfalls: Confusing solvent extraction names (Edeleanu/furfural) with dewaxing names, or assuming any low-boiling solvent implies Barisol. Final Answer: benzol (benzene) and ethylene dichloride

Question 3

Hydrocarbon series trend: As the number of carbon and hydrogen atoms increases in a hydrocarbon molecule (heavier, longer chains), how does the density of petroleum products generally change at the same temperature?

Accepted Answer

Introduction / Context: Product density is a fundamental property used for custody transfer, blending, and process design. Across homologous hydrocarbon series, molecular structure strongly influences density, boiling point, and viscosity. This question checks the standard qualitative trend with increasing carbon number at fixed conditions. Given Data / Assumptions: Comparison at the same temperature and pressure. Normal trend across straight-chain or mildly branched hydrocarbons. No unusual additives or dissolved gases that skew density. Concept / Approach: As molecular size (and average molecular weight) increases, intermolecular attractions rise and packing efficiency changes, leading to higher liquid density for series members at a given temperature. While branching can lower density relative to straight chains at the same carbon number, the primary effect of increasing carbon number itself is a density increase for petroleum cuts taken as mixtures centered at higher boiling ranges. Step-by-Step Solution: Recognize that heavier fractions (kerosene → diesel → gas oil → residue) exhibit increasing density.Relate bulk product density to average molecular weight of the cut.Select “increases” as the general trend with higher carbon/hydrogen count. Verification / Alternative check: Crude assay tables show monotonic rises in density (or API gravity decreases) as cut end points move to higher boiling ranges dominated by larger molecules. Why Other Options Are Wrong: Decreases/remains same: contradict refinery assay trends.Unpredictable: although branching matters, the direction across carbon number is well established.First increases then decreases: not typical across practical cut ranges. Common Pitfalls: Over-weighting branching effects and forgetting the overarching influence of carbon number on bulk petroleum product density. Final Answer: increases

Question 4

Fire safety property comparison: Among petrol (gasoline), kerosene, diesel, and furnace oil, which product has the highest flash point under standard test conditions?

Accepted Answer

Introduction / Context: Flash point is the lowest temperature at which a liquid gives off sufficient vapour to ignite momentarily. It increases as products become heavier and less volatile. This property informs storage and handling classifications and safety practices in refineries and depots. Given Data / Assumptions: Products considered: petrol, kerosene, diesel, furnace oil. Standard closed-cup or open-cup methods as per product specs. Comparison is qualitative: identify the highest flash point product. Concept / Approach: Light products (petrol) have very low flash points, kerosene is higher, diesel higher still, and residual fuels such as furnace oil exhibit the highest flash points due to minimal volatility at ambient conditions. Hence, furnace oil tops the list for flash point among the given options. Step-by-Step Solution: Order the products by volatility: petrol > kerosene > diesel > furnace oil (least volatile).Relate volatility to flash point: lower volatility → higher flash point.Select furnace oil as having the highest flash point. Verification / Alternative check: Typical specification ranges: petrol has a very low/negative flash by design; kerosene around tens of °C; diesel higher; furnace oil significantly higher still, often exceeding 60–90°C depending on grade. Why Other Options Are Wrong: Petrol: lowest flash point.Kerosene and diesel: intermediate values, not the highest.LPG: a gas at ambient; flash point concept differs from liquids. Common Pitfalls: Confusing “flash point” with “autoignition temperature”; these are different properties with different trends. Final Answer: Furnace oil (residual fuel oil)

Question 5

Feed selection for catalytic reforming: Rank the following naphtha sources in order of preference as feedstock to a catalytic reformer (best first), considering octane gain potential and contaminants: virgin naphtha, catalytic naphtha, coking naphth…

Accepted Answer

Introduction / Context: Catalytic reforming raises gasoline octane by aromatization and isomerization of naphtha. Feed selection affects catalyst life, hydrogen production, and octane uplift. Naphthas differ by origin: straight-run (virgin), catalytic (already processed), and coker (olefinic/contaminant-prone). Given Data / Assumptions: Reformer uses Pt/acid bifunctional catalysts. Desulfurized, denaphthenized, and dried feed is assumed but relative quality still matters. Preference is judged by octane response and fouling propensity. Concept / Approach: Virgin naphtha (especially naphthenic) responds best, giving large octane increase with manageable coke. Catalytic naphtha has already undergone conversion; its residual reforming potential is lower, making it second choice. Coker naphtha often contains diolefins, sulfur/nitrogen, and gum precursors, which poison catalysts and increase coke—least preferred. Step-by-Step Solution: Assess reformability: virgin > catalytic > coker.Consider contaminants: coker feeds carry the highest risk for rapid deactivation.Rank accordingly and select the option matching this order. Verification / Alternative check: Reformer design texts emphasize straight-run feeds with significant naphthene content for best aromatization and lowest fouling, while coker naphtha requires severe hydrotreating and still underperforms. Why Other Options Are Wrong: Any sequence placing coker above virgin or catalytic ignores contamination and lower reforming response.Placing catalytic first over virgin overstates remaining reformability of already-converted naphthas. Common Pitfalls: Equating high olefin content with reforming benefit; reformers prefer paraffinic/naphthenic feeds, not unstable olefinic streams. Final Answer: virgin naphtha → catalytic naphtha → coking naphtha

Question 6

Legacy additive knowledge: Tetra-ethyl lead (TEL) was historically added to gasoline primarily to achieve which performance improvement under spark-ignition conditions?

Accepted Answer

Introduction / Context: Before unleaded regulations, TEL was the dominant antiknock additive in motor gasoline. Octane number expresses knock resistance in spark-ignition engines; higher octane enables higher compression ratios and improved performance without detonation. Given Data / Assumptions: Spark-ignition engine context (not diesel). Antiknock function targets end-gas autoignition suppression. Other listed properties (smoke point, pour point, gum) are unrelated or secondary. Concept / Approach: TEL enhances knock resistance by interfering with radical chain reactions in the end-gas region, effectively raising both Research and Motor octane numbers of the blended fuel at small treat rates. It neither improves diesel cetane nor directly addresses pour point or smoke point limitations. Step-by-Step Solution: Identify the property targeted by antiknock additives: octane number.Associate TEL with strong octane blending value.Select “increase its octane number.” Verification / Alternative check: Historical refinery blending data show substantial octane uplift with milliliter-per-gallon doses of TEL, validating its use before phase-out for environmental reasons. Why Other Options Are Wrong: Smoke point: relevant for kerosene/jet, not gasoline.Gum formation: controlled by stabilization and additives; TEL is not a gum inhibitor.Pour point: a cold-flow property for heavier fuels.Cetane: pertains to diesel autoignition quality, opposite of octane’s role. Common Pitfalls: Mixing diesel and gasoline quality metrics (cetane vs octane) or assuming all additives solve multiple unrelated properties. Final Answer: increase its octane number

Question 7

Objective of cracking operations: In refinery conversion, the primary purpose of cracking heavy fractions is to maximize the yield of which target product range?

Accepted Answer

Introduction / Context: Cracking processes (thermal and catalytic) split large hydrocarbon molecules into smaller, more valuable products. The economic driver historically has been to increase gasoline production, given its demand in transport markets. Given Data / Assumptions: Feedstocks: gas oils and residues. Processes: FCC, hydrocracking, visbreaking/coking (for severity control). Target pool economics prioritize light liquids (C5+ gasoline range). Concept / Approach: Fluid catalytic cracking and hydrocracking are specifically designed to maximize gasoline and middle distillates from heavier feeds. While coke and gases are by-products, they are not the main objective; lubricant base oils and petrolatum are produced in separate lube processing schemes, not by cracking severity aimed at gasoline. Step-by-Step Solution: Identify cracking’s function: break heavy molecules to lighter fractions.Link market value: gasoline range products have high value and demand.Select “gasoline” as the primary objective. Verification / Alternative check: Unit performance KPIs for FCC include conversion to gasoline and light cycle oil, with coke minimized to protect catalyst and heat balance, confirming the main aim. Why Other Options Are Wrong: Lube oil and petrolatum are lube refinery products, not cracking targets.Coke is an undesired by-product limiting yields.Sulfur-free kerosene is addressed by hydrotreating, not cracking per se. Common Pitfalls: Equating high conversion with success even when coke increases; the goal is liquid yield and gasoline quality, not coke production. Final Answer: gasoline

Question 8

Desired aromatic content — product suitability: Aromatics are considered desirable constituents primarily in which petroleum product because they raise antiknock quality (octane)?

Accepted Answer

Introduction / Context: Different fuel/product classes prefer different hydrocarbon families. Aromatics have high octane numbers but can negatively affect other properties such as smoke point or ignition quality. Matching composition to product service is central to refining and blending decisions. Given Data / Assumptions: Products considered: gasoline, kerosene/jet, diesel, lube oils. Octane (SI engines) vs cetane (CI engines) distinction is assumed known. Kerosene smoke point and lube solvency trade-offs are considered. Concept / Approach: Aromatics raise octane and are therefore beneficial in petrol blending up to regulatory/environmental limits. In diesel, aromatics lower cetane (worse ignition quality). In kerosene/jet, excess aromatics reduce smoke point and can impair combustor performance. Lubricating oils favor paraffinic or balanced paraffinic-naphthenic bases; high aromatics hurt oxidation stability though provide solvency, so they are not broadly “desired.” Step-by-Step Solution: Relate aromatics to octane → benefit gasoline.Relate aromatics to cetane → harm diesel ignition quality.Relate aromatics to smoke point → harm kerosene/jet burning quality.Conclude petrol (gasoline) is the product where aromatics are most desired. Verification / Alternative check: Catalytic reforming deliberately increases aromatics in reformate to raise gasoline octane; diesel hydrotreaters often aim to reduce aromatics to improve cetane. Why Other Options Are Wrong: Lubricating oil: excess aromatics reduce oxidation stability.Diesel: aromatics depress cetane number.Kerosene: high aromatics lower smoke point.LPG: mainly propane/butane; aromatics are not components. Common Pitfalls: Confusing octane benefits with universal desirability; each product has different property priorities and regulatory limits. Final Answer: petrol (gasoline)

Question 9

Watson (UOP) characterization factor: The characterization factor for crude petroleum oil (Kw = (Tb)^1/3 / SG at 60°F) typically lies around which value, indicative of an intermediate paraffinic-naphthenic nature?

Accepted Answer

Introduction / Context: The Watson characterization factor (also called UOP K-factor) is a widely used empirical index to describe the general nature of a petroleum fraction or crude using average boiling point and specific gravity. It helps infer whether a crude is more paraffinic (higher Kw) or more naphthenic/aromatic (lower Kw). Given Data / Assumptions: Kw = (Tb in Rankine)^1/3 / SG (60°F) for the stream. Typical crude values cluster roughly between 10 and 13. Higher Kw → paraffinic; lower Kw → naphthenic. Concept / Approach: Most world crudes have Kw near 11–12; values near 12.5 denote strongly paraffinic; near 10–10.5 denote naphthenic/asphaltic. Extremely low or high numbers (e.g., 3 or 28) are nonphysical for crude characterization under this definition and unit basis. Step-by-Step Solution: Recall the realistic Kw range for crude oils.Identify the central tendency: around 11–12.Select 11 as the representative option. Verification / Alternative check: Crude assay summaries commonly list Kw in the stated band, with paraffinic crudes > 12 and naphthenic crudes < 11. Why Other Options Are Wrong: 3, 22, 28: outside plausible crude Kw range.7: far too low for crude per the standard definition. Common Pitfalls: Forgetting the temperature unit for Tb in the formula and miscomputing Kw magnitude; the cube-root form compresses variation. Final Answer: 11

Question 10

Polymer gasoline manufacture: In catalytic polymerization units that convert light olefins to higher-octane gasoline components, which catalyst system is commonly employed?

Accepted Answer

Introduction / Context: Catalytic polymerization (historical “polymer gasoline”) combines light olefins such as propylene and butylenes into higher molecular weight gasoline components. The process predates modern oligomerization/alkylation technologies and uses specific acid catalysts to drive carbon–carbon bond formation. Given Data / Assumptions: Feed: C3–C4 olefins from FCC or thermal cracking. Objective: produce high-octane gasoline blend stock. Catalyst options include acid and non-acid systems. Concept / Approach: A classic catalyst for polymerization to gasoline is phosphoric acid supported on kieselguhr (siliceous support). Strong solid acids promote olefin polymerization/oligomerization. Aluminium chloride is a Lewis acid for Friedel–Crafts reactions in different contexts; nickel is primarily for hydrogenation; vanadium pentoxide serves in oxidation (e.g., SO2→SO3), not olefin polymerization; an inert zeolite Y without an acid function would not be active for polymerization. Step-by-Step Solution: Match process class (olefin polymerization) with acid catalysis requirement.Identify the well-known catalyst: H3PO4 on kieselguhr.Exclude listed catalysts that do not fit the mechanism. Verification / Alternative check: Refinery process summaries list solid phosphoric acid (SPA) catalysts as standard for polymer gasoline/oligomer units, producing high-octane streams rich in branched components. Why Other Options Are Wrong: AlCl3: used in alkylation/acylation chemistry, corrosive and not the classic polymer gasoline catalyst.Nickel: hydrogenation, not polymerization.V2O5: oxidation catalyst.Zeolite Y (non-acid): insufficient acidity for polymerization. Common Pitfalls: Confusing polymerization with alkylation or hydrogenation; all three use different catalytic functionalities. Final Answer: phosphoric acid supported on kieselguhr

Question 11

Ignition quality reference scale (diesel): On the historical cetane number scale for compression-ignition fuels, the reference value assigned to alpha-methylnaphthalene is taken as what?

Accepted Answer

Introduction / Context: Cetane number quantifies diesel fuel ignition quality. The scale originally used two reference hydrocarbons: n-cetane (high ignition quality) and alpha-methylnaphthalene (poor ignition quality). Understanding the endpoints of this scale is foundational in fuel testing. Given Data / Assumptions: CFR engine test methods define cetane number. Original references: n-cetane (assigned 100) and alpha-methylnaphthalene (assigned 0). Modern practice often uses heptamethylnonane (isocetane) as a 15 reference, but the 0-point legacy still appears in exams. Concept / Approach: The conventional historical assignment places alpha-methylnaphthalene at the zero point due to its very poor auto-ignition tendency in CI engines, thereby setting the lower bound of the cetane scale. This provides a linear reference between poor and excellent ignition fuels for calibration and comparison. Step-by-Step Solution: Recall scale anchors: alpha-methylnaphthalene = 0; n-cetane = 100.Relate scale meaning: higher cetane number → shorter ignition delay.Select the zero assignment for alpha-methylnaphthalene. Verification / Alternative check: Standards literature notes the later substitution of isocetane (15) for handling reasons, but the original 0 assignment for alpha-methylnaphthalene remains the canonical teaching point. Why Other Options Are Wrong: 100: reserved for n-cetane, the high-quality reference fuel.50: arbitrary midpoint, not a reference assignment.Infinite: not meaningful in this scale.15: relates to isocetane, not alpha-methylnaphthalene. Common Pitfalls: Confusing the updated reference pair (isocetane 15) with the historical zero point; the question explicitly names alpha-methylnaphthalene. Final Answer: 0

Question 12

LPG behaviour at ambient conditions When liquefied petroleum gas (LPG)—a mixture mainly of propane and butane—is released from its storage cylinder to normal atmospheric pressure and typical room temperature, what physical state and relative density…

Accepted Answer

Introduction / Context: LPG (liquefied petroleum gas) is widely used as a domestic and industrial fuel. It is stored as a liquid under pressure, but its behaviour at normal ambient conditions determines leak dispersion, ventilation design, and safety measures. This question checks whether you know the physical state LPG assumes and whether its vapour is heavier or lighter than air when released to atmospheric pressure and typical room temperature. Given Data / Assumptions: LPG is primarily a propane–butane mixture with small amounts of other light hydrocarbons. Conditions: approximately 1 atm and room temperature (around 20–30 °C). We are concerned with the state of the released LPG and its density relative to air. Concept / Approach: Under pressure, LPG is a liquid. When the valve is opened and the pressure drops to atmospheric, part of the liquid flashes to vapour and chills the remaining liquid. At ordinary ambient temperatures above the boiling points of propane and butane at 1 atm, LPG does not remain a bulk liquid; it becomes a gas. The molecular weights of propane (~44) and n-butane (~58) exceed the average molecular weight of air (~29), so LPG vapour is denser than air and tends to settle in low spots unless dispersed. Step-by-Step Solution: Identify the phase change: depressurisation from cylinder pressure to 1 atm causes flashing and vapour formation.Check boiling points: propane and butane boil far below typical room temperature at 1 atm, ensuring a gaseous state.Compare molecular weights: LPG vapour > air → heavier-than-air behaviour.Conclude: at ambient conditions, LPG is a gas heavier than air. Verification / Alternative check: MSDS sheets and safety codes note that LPG vapours accumulate at floor level, confirming heavier-than-air characteristics, and that LPG is stored as a liquid only under pressure or at low temperature. Why Other Options Are Wrong: Gas lighter than air: Incorrect; propane/butane vapours are denser than air. Liquid lighter/heavier than water: Not applicable at 1 atm and room temperature; LPG does not remain a bulk liquid. Common Pitfalls: Assuming “gas cylinder” implies a gas remains liquid after release; it only stays liquid while pressurised or cold. Final Answer: Gas heavier than air

Question 13

Definition check in petroleum terminology In refinery and crude assay language, a “sour crude” refers to a crude oil that contains appreciable amounts of which class of compounds?

Accepted Answer

Introduction / Context: Crudes are broadly classified as “sweet” or “sour,” a distinction that drives refinery processing severity, hydrogen demand, and product sulphur specifications. Recognising what makes a crude “sour” is essential for understanding hydrotreating loads and corrosion management. Given Data / Assumptions: The term “sour” is a standard industry descriptor. We seek the primary chemical reason behind the label. Other heteroatom compounds may be present but are not the defining feature for “sour.” Concept / Approach: “Sour” denotes significant sulphur-containing species (e.g., hydrogen sulphide, mercaptans, sulphides, thiophenes). These compounds raise corrosion risk, poison catalysts, and necessitate desulphurisation. While asphalt (asphaltenes), wax (long-chain paraffins), and nitrogen compounds influence processing, they do not define the “sour” classification. Step-by-Step Solution: Recall: sweet vs sour is a sulphur-based classification.Identify the main offenders: H2S, mercaptans, thiophenic sulphur.Select “Sulphur compounds.” Verification / Alternative check: Crude specs list total sulphur wt% as the headline measure for sweetness; many trading contracts price based on sulphur grade. Why Other Options Are Wrong: Asphalt / Wax: Affect viscosity, pour point, and residue yield, not “sourness.” Nitrogen compounds: Important for catalyst poisoning and color, but not the naming basis. Common Pitfalls: Equating dark color or high viscosity with sourness; a crude can be heavy yet sweet if sulphur is low. Final Answer: Sulphur compounds

Question 14

Catalytic cracking operating trends Which statement set correctly captures typical effects in catalytic cracking units regarding pressure, temperature, and catalyst-to-oil (C/O) ratio?

Accepted Answer

Introduction / Context: Fluid catalytic cracking (FCC) and related catalytic cracking processes convert heavy feeds to lighter products. Operating variables such as pressure, temperature, and catalyst-to-oil ratio (C/O) strongly influence conversion, selectivity, and product quality. This question checks whether you understand common qualitative trends used in troubleshooting and optimization. Given Data / Assumptions: Conventional catalytic cracking of gas oils (not hydrocracking). Comparison is qualitative and exam-style, using widely taught rules of thumb. Octane refers to gasoline pool octane from the cracker. Concept / Approach: (a) Higher reactor pressure promotes hydrogen transfer reactions, which saturate olefins and increase paraffinicity. This reduces gasoline octane, because olefins and aromatics usually carry higher octane than paraffins. (b) At higher temperature, selectivity shifts toward lighter gases and LPG; for a set overall conversion target, the incremental gasoline yield can decline due to increased cracking severity, even as gasoline octane tends to rise. (c) Raising C/O generally increases conversion since more active sites contact the feed per unit time, improving cracking extent up to hydrodynamic and diffusion limits. Step-by-Step Solution: Evaluate (a): pressure ↑ → hydrogen transfer ↑ → gasoline olefins ↓ → octane ↓ → True.Evaluate (b): temperature ↑ at fixed conversion shifts selectivity to LPG/dry gas → gasoline yield ↓ → True.Evaluate (c): C/O ↑ provides more catalyst activity per unit feed → conversion ↑ → True.Therefore, the combined choice “All of (a), (b) and (c)” is correct. Verification / Alternative check: FCC operating guides show octane falling with pressure due to hydrogen transfer, and yield curves shifting with temperature and C/O as described. Why Other Options Are Wrong: Any single-statement option omits other true effects; the comprehensive answer is the combined one. Common Pitfalls: Assuming higher pressure always improves quality; in cracking, it can decrease gasoline octane. Also, conflating total conversion increase with gasoline yield increase—selectivity matters. Final Answer: All of (a), (b) and (c)

Question 15

Hydrocracking operating window Hydrocracking is carried out under what general combination of pressure and temperature compared with other refinery conversion processes?

Accepted Answer

Introduction / Context: Hydrocracking upgrades heavy feeds (e.g., vacuum gas oil) into middle distillates and naphtha using hydrogen and bifunctional catalysts. Recognizing its typical pressure–temperature regime helps differentiate it from catalytic cracking, reforming, and hydrotreating. Given Data / Assumptions: Bifunctional catalysts (acid + metal) are used. Hydrogen partial pressure is substantial to suppress coke and saturate olefins/aromatics. We compare qualitative ranges only. Concept / Approach: Hydrocracking requires high temperature to crack heavy molecules and high hydrogen partial pressure to maintain catalyst life, control coke, and saturate intermediates. Operating pressures are typically several tens to over a hundred bar, and temperatures are in the several hundred Celsius range—thus “high–high” compared with many other units. Step-by-Step Solution: Note cracking requires thermal energy → elevated temperature.Coke suppression and saturation need abundant hydrogen → elevated pressure.Therefore, select “High pressure and high temperature.” Verification / Alternative check: Standard process summaries list hydrocracking with the highest pressures among mainline refinery conversion units. Why Other Options Are Wrong: Low–low / High–low / Low–high: Do not match the simultaneous needs for cracking kinetics and hydrogen effects. Common Pitfalls: Confusing hydrotreating (also high pressure but generally lower severity) with hydrocracking; hydrocracking is more severe in both temperature and conversion level. Final Answer: High pressure and high temperature

Question 16

Diesel ignition quality improvers Which additive is commonly used to increase the cetane number of diesel fuel in refinery blending or aftermarket treatment?

Accepted Answer

Introduction / Context: Cetane number indicates the ignition quality of diesel fuel—the higher the cetane, the shorter the ignition delay and the smoother the combustion. Refiners and blenders sometimes add cetane improvers to meet specifications, especially when feedstocks or seasonality reduce natural cetane. Given Data / Assumptions: The question asks for a typical cetane improver used in practice. Leaded gasoline additives (tetraethyl lead, tetramethyllead) relate to octane, not cetane. We focus on the generic compound class, not a specific brand. Concept / Approach: Nitrate-based additives (e.g., ethyl nitrate, 2-ethylhexyl nitrate) are widely used cetane improvers. They decompose to yield radicals that promote low-temperature pre-flame reactions, thereby reducing ignition delay. Tetraethyl lead and tetramethyllead are historical anti-knock agents for spark-ignition gasoline, not diesel cetane boosters, and are phased out for environmental reasons. Step-by-Step Solution: Identify nitrate esters as cetane improvers.Recognise ethyl nitrate as a representative example.Exclude lead alkyls which affect octane, not cetane. Verification / Alternative check: Fuel additive references list nitrate esters as the go-to cetane improvers, with typical treat rates in ppm to low thousands depending on base fuel quality. Why Other Options Are Wrong: Tetraethyl lead / Tetramethyllead: Gasoline octane improvers, environmentally restricted; not used for diesel cetane. None of these: Incorrect because a valid cetane improver is listed. Common Pitfalls: Confusing octane (spark-ignition anti-knock) with cetane (compression-ignition ignition quality). Final Answer: Ethyl nitrate

Question 17

Hydrocarbon families – general formula recall Under standard textbook conventions, what is the general formula for naphthenes (cycloalkanes), and how does it relate to olefins?

Accepted Answer

Introduction / Context: Recognising family formulas helps in quick classification of petroleum hydrocarbons and in reasoning about properties such as density, reactivity, and hydrogen-to-carbon ratios. Naphthenes (cycloalkanes) often appear in refinery chemistry questions alongside paraffins and olefins. Given Data / Assumptions: Naphthenes are saturated ring compounds (cycloalkanes). We compare their general formula to that of olefins. Standard classroom conventions apply. Concept / Approach: Straight-chain alkanes have formula CnH2n+2. Forming one ring removes two hydrogens relative to the open chain, giving cycloalkanes the formula CnH2n. Olefins (alkenes) also have CnH2n due to one double bond lowering hydrogen count by two. Thus, naphthenes and olefins share the same general formula, even though their structures and properties differ. Step-by-Step Solution: Start from alkanes: CnH2n+2.Apply one ring formation (saturation retained): subtract 2 H → CnH2n.Note the same expression holds for alkenes with one double bond: CnH2n. Verification / Alternative check: Examples like cyclohexane (C6H12) and 1-hexene (C6H12) confirm that structural differences can share an empirical formula. Why Other Options Are Wrong: CnH2n+2: Open-chain alkanes (paraffins), not naphthenes. CnH2n-6: Typical for monoaromatics such as benzene (n = 6); not cycloalkanes. CnHn-4: Not a standard family formula. Common Pitfalls: Assuming a unique mapping from formula to structure; many isomers and families can share the same empirical formula. Final Answer: CnH2n

Question 18

Reforming reactor practice – purpose of hydrogen recycle In catalytic reforming, why is byproduct hydrogen recycled back to the reactor along with the naphtha feed?

Accepted Answer

Introduction / Context: Catalytic reforming converts low-octane naphtha into high-octane reformate and produces significant hydrogen. Most units recycle part of this hydrogen back to the reactors. Understanding the purpose of this recycle clarifies how reformers achieve long run lengths and high product quality. Given Data / Assumptions: Feed: hydrotreated naphtha rich in naphthenes/paraffins. Reactions: dehydrogenation of naphthenes to aromatics, isomerisation, limited hydrocracking. Catalysts: bifunctional (metal/acid), sensitive to coke and poisons. Concept / Approach: High hydrogen partial pressure suppresses coke formation, limits polymerisation of unsaturates, and helps keep catalyst surfaces clean, thereby reducing deactivation and poisoning effects (e.g., from trace sulphur/nitrogen). Hydrogen also shifts certain equilibria favourably for stability, though reforming’s signature octane gain comes from dehydrogenation and cyclisation. Hydrogen recycle is not intended to heat the reactor, hold pressure mechanically, or fully hydrogenate the feed to paraffins (which would defeat the reforming objective). Step-by-Step Solution: Identify key reformer risks: coke laydown and catalyst poisoning.Recall mitigation: maintain high H2 partial pressure via recycle.Select the option explicitly mentioning suppressing coking and obviating poisoning. Verification / Alternative check: Reformer operating manuals specify hydrogen-to-hydrocarbon ratio targets to maintain catalyst activity and product stability. Why Other Options Are Wrong: Maintain reaction temperature: Temperature is controlled by fired heaters/interheaters, not H2 recycle directly. Sustain pressure: Compressors/valving set pressure; recycle H2 serves chemistry, not mechanical pressurisation alone. Hydrogenate feed completely: Counterproductive to reforming’s aromatics/isomerisation goals. Common Pitfalls: Confusing reforming with hydrotreating; reformers do not aim to saturate everything, they aim for octane improvement while managing coke. Final Answer: Obviate catalyst poisoning and suppress coking by maintaining high hydrogen partial pressure

Question 19

Interpreting specific gravity changes For petroleum fractions, an increase in specific gravity typically indicates what change in composition and properties?

Accepted Answer

Introduction / Context: Specific gravity (or API gravity) is a quick indicator of hydrocarbon family distribution in petroleum fractions. Heavier, denser streams generally contain more aromatics and polars, while lighter, less dense streams are richer in paraffins. Understanding this relationship helps predict combustion behaviour and refining pathways. Given Data / Assumptions: Comparisons are qualitative and typical. We relate density to composition (paraffins vs aromatics). H/C ratio trends mirror family distribution. Concept / Approach: Aromatics possess ring structures with lower hydrogen content per carbon than paraffins. This makes them denser on average. Therefore, as specific gravity increases (API decreases), the aromatic fraction usually rises, and the paraffinic fraction falls. H/C ratio declines with higher aromaticity. Net heating value per weight does not increase with aromatics; paraffins tend to have slightly higher heating value per unit mass. Step-by-Step Solution: Connect density ↑ with aromaticity ↑ and paraffinity ↓.Note that H/C ratio trends opposite to aromatics: more aromatics → lower H/C.Select “Increase in aromatic content” as the most direct implication. Verification / Alternative check: Assay correlations show API gravity inversely correlates with aromatic content; smoke point and aniline point trends corroborate this. Why Other Options Are Wrong: Decrease in paraffin content: Also generally true, but the question asks for what the increase indicates most directly; the standard interpretation focuses on aromatics rising. Higher H/C ratio: Opposite; aromatics reduce H/C. Higher thermal energy per weight: Not supported; gravimetric heating value tends to be lower for more aromatic streams. Common Pitfalls: Confusing weight-based and volume-based heating values; also conflating API gravity with viscosity. Final Answer: Increase in aromatic content

Question 20

Crude distillation basics – topping unit The crude “topping” column (first-stage crude distillation) normally operates at what overall pressure regime?

Accepted Answer

Introduction / Context: The first major refinery separation step is the crude distillation unit (CDU), often called the topping unit, which separates crude into light gases, naphtha, kerosene, gas oils, and atmospheric residue. Knowing its pressure regime is foundational for understanding downstream unit feeds and operating constraints. Given Data / Assumptions: We refer to the atmospheric crude column (not the vacuum column). Minor pressure drops across trays/packing and overhead systems exist but do not change the classification. Units include preheat trains and a fired heater leading into the column. Concept / Approach: The topping column operates close to atmospheric pressure (slightly above to ensure positive flows and to accommodate pressure drops). Heavier fractions that would thermally degrade at their atmospheric boiling points are later separated under vacuum in a separate vacuum distillation column, not by raising pressure. Step-by-Step Solution: Identify that “topping” equals crude atmospheric distillation.Recall that vacuum service is a different unit for heavier cuts.Select “Atmospheric.” Verification / Alternative check: Standard refinery flow diagrams label the first column as atmospheric and the second as vacuum; operating pressures hover near 1 atm. Why Other Options Are Wrong: 10 atm / 3 atm: Far above normal CDU top pressure; would complicate equipment and not aid separation. Vacuum: This describes the VDU, not the CDU. Common Pitfalls: Thinking higher pressure improves fractionation; in distillation, pressure selection balances temperature limits and condenser duties. Final Answer: Atmospheric

Petroleum Refinery Engineering Questions