Difficulty: Easy
Correct Answer: very high
Explanation:
Introduction / Context:
Real capacitors are not perfect: in addition to the ideal capacitance, they exhibit dielectric losses and leakage. Engineers often use an equivalent circuit with a capacitance in parallel with a resistance to represent the insulation resistance or leakage path through the dielectric. Understanding what value of this resistance indicates a 'good' capacitor is crucial for low-loss filtering, energy storage, timing, and hold-up applications.
Given Data / Assumptions:
Concept / Approach:
The parallel resistance determines the DC leakage current and contributes to AC loss. A larger R_leak means less leakage and less power dissipated as heat. For a 'good' capacitor, we want negligible leakage and near-ideal energy storage, which corresponds to an R_leak that is as large as practically achievable (approaching open circuit). This also translates to a high parallel quality factor and a large time constant for charge retention.
Step-by-Step Solution:
Verification / Alternative check:
Datasheets specify insulation resistance (IR) or leakage current. High-grade film and ceramic capacitors show megaohm to gigaohm IR values, confirming that 'very high' leakage resistance is the desired characteristic.
Why Other Options Are Wrong:
'Negligible' or 'low' resistance would cause large leakage and high loss; 'high' is good but 'very high' best reflects the design goal; 'moderate' is inadequate for precision timing or energy storage.
Common Pitfalls:
Confusing the parallel leakage model with series ESR; ESR affects AC ripple but does not set DC leakage. Also, assuming all dielectric losses are captured by ESR alone ignores the parallel leakage path.
Final Answer:
very high
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