Capacitance of an isolated conducting sphere in vacuum What is the capacitance C of a single isolated conducting sphere of radius R in vacuum (permittivity ε0)?

Difficulty: Easy

Correct Answer: 4π ε0 R

Explanation:


Introduction / Context:
An isolated conducting sphere is a fundamental electrostatics configuration. Its capacitance defines how much charge it can store per unit potential relative to infinity. This result is widely used in high-voltage engineering, lightning protection, and as a building block for more complex capacitance calculations.


Given Data / Assumptions:

  • Perfect conductor shaped as a sphere of radius R.
  • Surrounded by vacuum (permittivity ε0), reference potential at infinity.
  • Electrostatic steady state; no nearby conductors or dielectrics.


Concept / Approach:

For a charged isolated sphere, the electric field outside is identical to that of a point charge at the center. The potential at the surface relative to infinity is V = (1 / (4π ε0)) * (Q / R). The capacitance is C = Q / V, yielding C = 4π ε0 R, linear in the radius.


Step-by-Step Solution:

Write surface potential: V = (1/(4π ε0)) * Q / R.Capacitance definition: C = Q / V.Compute: C = Q / [(1/(4π ε0)) * Q / R] = 4π ε0 R.


Verification / Alternative check:

Dimensional check: ε0 has units C^2/(N·m^2); multiplying by length R gives farads, as required. The result also matches limiting cases for large R (larger C) and small R (smaller C).


Why Other Options Are Wrong:

2π ε0 R is off by a factor 2; 4π ε0 R^2 has wrong length dependence; 4π lacks units and parameters.


Common Pitfalls:

Confusing the sphere–plane or sphere–shell capacitance with the isolated sphere value; nearby conductors change the effective capacitance.


Final Answer:

4π ε0 R

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