In C, basic strlen on a digit-only literal: what is printed? #include<stdio.h> #include<string.h> int main() { printf("%d ", strlen("123456")); return 0; }

Introduction / Context:This is a direct application of strlen to a string literal. strlen counts characters up to but not including the first null terminator.

Given Data / Assumptions:

• The literal is "123456".
• No embedded nulls are present.

Concept / Approach:strlen("abcdef") returns the number of visible characters before the implicit '\0'. Here, that count is the number of digits in the literal.

Step-by-Step Solution:List characters: 1 2 3 4 5 6 → 6 characters.strlen returns 6, which printf prints as 6.

Verification / Alternative check:Compare with sizeof "123456" which would be 7 (adds the terminating null). This highlights the difference between strlen (logical length) and sizeof (storage in bytes for a literal).

Why Other Options Are Wrong:(12) doubles the count; (7) confuses with sizeof. (2) and (0) have no basis here.

Common Pitfalls:Confusing strlen with sizeof for string literals.

Final Answer:6