Q: C#.NET string interning and object references: consider the code String s1, s2; s1 = 'Hi'; s2 = 'Hi'; Which statements about object creation and references are true?

Introduction / Context: This item tests understanding of string interning and reference behavior in C#.NET. String literals are interned, which can cause multiple variables initialized with the same literal to point to the same object instance. Given Data / Assumptions: Two string variables s1 and s2. Both assigned the same literal 'Hi'. Statements to evaluate include whether objects are created with or without new, and whether references point to the same instance. Concept / Approach: In .NET, string literals are interned. Assigning the same literal to two variables does not create two different heap objects; both references point to the interned single instance. Creating strings without new is perfectly legal through literals. Step-by-Step Solution: 1) 'String objects cannot be created without using new.' → False: literals create interned strings.2) 'Only one object will get created.' → True due to interning.3) 's1 and s2 both will refer to the same object.' → True: both refer to interned 'Hi'.4) 'Two objects will get created…' → False.5) 's1 and s2 are references to the same object.' → True (same as 3). Verification / Alternative check: Use Object.ReferenceEquals(s1, s2) → returns true. Using new string('H',1) etc. would bypass interning unless explicitly interned. Why Other Options Are Wrong: Any option including 1 or 4 is incorrect because they contradict interning and literal semantics. Common Pitfalls: Confusing content equality with reference equality; assuming every assignment creates a new object on the heap. Final Answer: 2, 3, 5

Q: C#.NET String.Insert: determine the output of String s1 = 'Nagpur'; String s2; s2 = s1.Insert(6, 'Mumbai'); Console.WriteLine(s2); What is printed?

Introduction / Context: This checks understanding of the String.Insert method, which returns a new string by inserting a specified substring at a given index (0-based). Given Data / Assumptions: s1 = 'Nagpur' (length 6). We call s1.Insert(6, 'Mumbai'). Index 6 equals the length of s1, so insertion occurs at the end. Concept / Approach: The Insert method does not mutate s1 (strings are immutable); it produces a new string with the substring inserted at the specified index: prefix up to index + inserted text + remainder. If the index is equal to the original length, it appends. Step-by-Step Solution: Compute length: 'Nagpur' → 6.Insert at index 6 (after the last character).Result: 'Nagpur' + 'Mumbai' → 'NagpurMumbai'. Verification / Alternative check: Replace the index with 0 to see a different effect ('MumbaiNagpur'). Attempting an index > length would throw an ArgumentOutOfRangeException. Why Other Options Are Wrong: 'NagpuMumbair' misplaces letters. 'Nagpur Mumbai' implies insertion of a space not present in the call. 'Mumbai' or 'Nagpur' would imply ignoring one of the strings; that is not the behavior of Insert. Common Pitfalls: Confusing Insert with Concat and off-by-one errors with indexes. Final Answer: NagpurMumbai

Question 1

C#.NET strings: What will be printed by the following code when comparing two differently cased strings?  String s1 = 'Five Star'; String s2 = 'FIVE STAR'; int c; c = s1.CompareTo(s2); Console.WriteLine(c);  Choose the correct result of the call to …

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Introduction / Context: This question examines how String.CompareTo behaves in C#.NET. The method performs a case-sensitive, culture-aware comparison and returns an integer: less than 0 if the instance precedes the argument, 0 if equal, and greater than 0 if it follows. Given Data / Assumptions: s1 = 'Five Star' s2 = 'FIVE STAR' c = s1.CompareTo(s2) and then Console.WriteLine(c) CompareTo returns a signed int, not necessarily only -1, 0, or 1, but commonly those values. Concept / Approach: Comparison is lexicographic and case-sensitive in the current culture. The first differing character controls the result. Uppercase and lowercase letters have different sort values; typically lowercase letters follow uppercase in case-sensitive comparisons. Step-by-Step Solution: Compare character by character: 'F' vs 'F' → equal.Next: 'i' (105) vs 'I' (73) → since 105 > 73, s1 is greater than s2.Therefore, CompareTo returns a positive integer. In typical outputs this prints 1. Verification / Alternative check: Calling String.Compare(s1, s2) with default overloads also yields a positive value. Using StringComparer.OrdinalIgnoreCase (not used here) would yield equality (0), highlighting the effect of case sensitivity. Why Other Options Are Wrong: 0 implies equality (not true due to case). -1 or -2 indicate s1 < s2, which contradicts the character comparison. 2 is not the typical printed value; while any positive value technically indicates 'greater than', standard examples show 1. Common Pitfalls: Assuming comparisons are case-insensitive by default or that the numeric values correspond to character code differences directly; CompareTo abstracts that away and only guarantees sign. Final Answer: 1

Question 2

C#.NET string interning and object references: consider the code  String s1, s2; s1 = 'Hi'; s2 = 'Hi';  Which statements about object creation and references are true?

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Introduction / Context: This item tests understanding of string interning and reference behavior in C#.NET. String literals are interned, which can cause multiple variables initialized with the same literal to point to the same object instance. Given Data / Assumptions: Two string variables s1 and s2. Both assigned the same literal 'Hi'. Statements to evaluate include whether objects are created with or without new, and whether references point to the same instance. Concept / Approach: In .NET, string literals are interned. Assigning the same literal to two variables does not create two different heap objects; both references point to the interned single instance. Creating strings without new is perfectly legal through literals. Step-by-Step Solution: 1) 'String objects cannot be created without using new.' → False: literals create interned strings.2) 'Only one object will get created.' → True due to interning.3) 's1 and s2 both will refer to the same object.' → True: both refer to interned 'Hi'.4) 'Two objects will get created…' → False.5) 's1 and s2 are references to the same object.' → True (same as 3). Verification / Alternative check: Use Object.ReferenceEquals(s1, s2) → returns true. Using new string('H',1) etc. would bypass interning unless explicitly interned. Why Other Options Are Wrong: Any option including 1 or 4 is incorrect because they contradict interning and literal semantics. Common Pitfalls: Confusing content equality with reference equality; assuming every assignment creates a new object on the heap. Final Answer: 2, 3, 5

Question 3

C#.NET String.Insert: determine the output of  String s1 = 'Nagpur'; String s2; s2 = s1.Insert(6, 'Mumbai'); Console.WriteLine(s2);  What is printed?

Accepted Answer

Introduction / Context: This checks understanding of the String.Insert method, which returns a new string by inserting a specified substring at a given index (0-based). Given Data / Assumptions: s1 = 'Nagpur' (length 6). We call s1.Insert(6, 'Mumbai'). Index 6 equals the length of s1, so insertion occurs at the end. Concept / Approach: The Insert method does not mutate s1 (strings are immutable); it produces a new string with the substring inserted at the specified index: prefix up to index + inserted text + remainder. If the index is equal to the original length, it appends. Step-by-Step Solution: Compute length: 'Nagpur' → 6.Insert at index 6 (after the last character).Result: 'Nagpur' + 'Mumbai' → 'NagpurMumbai'. Verification / Alternative check: Replace the index with 0 to see a different effect ('MumbaiNagpur'). Attempting an index > length would throw an ArgumentOutOfRangeException. Why Other Options Are Wrong: 'NagpuMumbair' misplaces letters. 'Nagpur Mumbai' implies insertion of a space not present in the call. 'Mumbai' or 'Nagpur' would imply ignoring one of the strings; that is not the behavior of Insert. Common Pitfalls: Confusing Insert with Concat and off-by-one errors with indexes. Final Answer: NagpurMumbai

Question 4

C#.NET: Correct ways to convert a String to an int (assume s = '123'). Select all valid C# approaches.

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Introduction / Context: Converting text to numeric types is routine. In C#, several standard methods exist to convert a numeric string to an int, each with different behavior for invalid input. Given Data / Assumptions: String s = '123'; and int i; Evaluate: casting, int.Parse, Int32.Parse, Convert.ToInt32, CInt. Concept / Approach: int.Parse and Int32.Parse are equivalent and parse a string containing digits into an integer (throwing on invalid format). Convert.ToInt32 also parses strings and handles null differently (returns 0 for null). Direct casting from string to int is not allowed. CInt is a VB keyword, not valid C# syntax. Step-by-Step Solution: Attempt i = (int)s; → invalid in C#.Use i = int.Parse(s); → valid.Use i = Int32.Parse(s); → valid.Use i = Convert.ToInt32(s); → valid.Use i = CInt(s); → invalid in C#. Verification / Alternative check: For safe parsing, int.TryParse(s, out i) avoids exceptions on bad input and returns a boolean. Why Other Options Are Wrong: Any combination including 1 or 5 is incorrect because casting a string to int is illegal and CInt is not a C# construct. Common Pitfalls: Confusing C# with VB syntax; forgetting to handle invalid inputs and culture-specific formats. Final Answer: 2, 3, 4

Question 5

C#.NET strings: What is the correct way to compare two string variables s1 and s2 for equality of contents (not assignment)?

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Introduction / Context: Comparing strings in C#.NET can be done via operators or methods. Understanding which operator compares contents versus references is vital to avoid subtle bugs. Given Data / Assumptions: s1 and s2 are variables of type string. We want to test if their contents are equal. Concept / Approach: In C#, the == operator is overloaded for string to perform value (content) equality. Likewise, string.Equals compares contents (with overloads for comparison options). Assignment (=) does not compare; it overwrites references. The is operator tests type, not equality. C-style strcmp is not part of C#. Step-by-Step Solution: s1 == s2 → compares contents and returns a boolean.s1.Equals(s2) → also compares contents and returns a boolean (valid alternative).s1 = s2 → assignment, not comparison; wrong.s1 is s2 → type test, not equality; wrong.strcmp → not available in C#; wrong. Verification / Alternative check: To compare references (object identity), use Object.ReferenceEquals(s1, s2). That is different from content equality. Why Other Options Are Wrong: They either change the variable (=), test type (is), or use non-C# functions. Common Pitfalls: Mixing up content equality with reference equality; assuming == compares references for strings (in C#, it does content comparison). Final Answer: s1 == s2

Question 6

C#.NET strings vs. StringBuilder: choose the correct statement about mutability and immutability.

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Introduction / Context: This tests whether you know that string in C# is immutable, whereas StringBuilder provides a mutable buffer for efficient in-place-like modifications. Given Data / Assumptions: Statement: Strings built using String are immutable; StringBuilder instances are mutable. Concept / Approach: Immutability means any apparent modification of a string produces a new instance, leaving the original unchanged. StringBuilder maintains an internal resizable buffer permitting operations like Append, Insert, and Remove without creating a new string each time (until you call ToString()). Step-by-Step Solution: Create string s = 'a'; then s += 'b'; → returns a new string 'ab'.Create var sb = new StringBuilder('a'); then sb.Append('b'); → same sb buffer now holds 'ab'. Verification / Alternative check: Use a memory profiler or check Object.ReferenceEquals before and after modifying a string versus a StringBuilder. Why Other Options Are Wrong: Marking the statement as False contradicts the documented behavior of both types. Common Pitfalls: Building long strings with + in loops, causing unnecessary allocations; prefer StringBuilder for repeated concatenations. Final Answer: True

Question 7

Where are C#.NET String objects created? Choose the correct statement about the memory location of a String.

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Introduction / Context: Understanding where objects live clarifies performance and lifetime semantics in .NET. Strings in C# are reference types managed by the garbage collector. Given Data / Assumptions: C# strings are of type System.String, a reference type. The .NET runtime manages memory for reference types on the managed heap. Concept / Approach: Local variables may be stored on the stack, but the data for reference type instances (like strings) is allocated on the heap. The variable holds a reference to that heap object. String is not a primitive in C#; it is a reference type with special language support. Step-by-Step Solution: Option A → False: only references can be on the stack; object data for strings is heap-allocated.Option B → False: size does not change the allocation model for strings.Option C → False: string is not a primitive in C#.Option D → Incorrect syntax and unnecessary; typical construction uses literals or new string(char[]) overloads.Option E → True: String instances are on the heap. Verification / Alternative check: Inspect IL or use a debugger: references are local; object memory is heap-based. Why Other Options Are Wrong: They either misuse syntax or conflate variable storage (references) with object storage (heap). Common Pitfalls: Assuming small objects are placed on the stack automatically; in .NET, object allocation strategy depends on type category, not just size. Final Answer: A String is created on the heap.

Question 8

String and StringBuilder in C#.NET: select the correct statements.  1) Two strings can be concatenated using s3 = s1 + s2; 2) String is a primitive in C#.NET. 3) A string built with StringBuilder is mutable. 4) A string built with String is immutabl…

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Introduction / Context: This question reviews fundamental properties of string and StringBuilder and the standard concatenation syntax in C#. Given Data / Assumptions: Statements to validate include concatenation forms and mutability claims. Concept / Approach: In C#, strings are immutable, and the + operator concatenates strings. StringBuilder provides a mutable buffer for efficient concatenations or edits. The & concatenation operator is a VB feature, not C#. Step-by-Step Solution: 1) s3 = s1 + s2 → Valid in C#.2) 'String is a primitive' → False; it is a reference type with special handling.3) StringBuilder-built strings are mutable → True (the builder is mutable; resulting ToString() is immutable).4) Strings are immutable → True.5) s3 = s1 & s2 → Not C# syntax; false. Verification / Alternative check: Creating a StringBuilder and appending confirms mutability; attempting to modify an existing string shows it produces a new instance. Why Other Options Are Wrong: Options including 2 or 5 assert incorrect claims about primitives or use non-C# operators. Common Pitfalls: Assuming VB operators apply in C#; forgetting the performance implications of repeated + in loops. Final Answer: 1, 3, 4

Question 9

Comparing string contents in C#.NET: which of the following are valid ways to determine if two strings s1 and s2 have equal contents?  1) if(s1 = s2) 2) if(s1 == s2) 3) int c; c = s1.CompareTo(s2); 4) if(strcmp(s1, s2)) 5) if (s1 is s2)

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Introduction / Context: This problem focuses on correct techniques for string equality checks in C#.NET. Understanding operators and methods available in the .NET framework helps avoid logic errors. Given Data / Assumptions: We have two string references s1 and s2. We want to know whether their contents are equal. Concept / Approach: In C#, the == operator is overloaded for string to perform content comparison. CompareTo returns 0 when two strings are equal. C-style strcmp is not a C# function. The is operator checks type compatibility, not content equality. Assignment (=) is not a comparison. Step-by-Step Solution: 2) if (s1 == s2) → Valid for content equality.3) int c = s1.CompareTo(s2); → Valid basis; equality holds if c == 0.1) if (s1 = s2) → Invalid; assignment, not comparison.4) strcmp → Not part of C#.5) s1 is s2 → Type test, not equality. Verification / Alternative check: Using s1.Equals(s2) is another standard approach that returns a boolean, with overloads for culture and case options. Why Other Options Are Wrong: They include non-C# functions, type checks, or misuse assignment. Common Pitfalls: Forgetting to compare CompareTo’s result to zero, and confusing identity vs. equality. Final Answer: 2, 3

Question 10

Copying the contents of one string to another in C#.NET: choose the statement that correctly creates a new string with the same contents as an existing one.

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Introduction / Context: Copying strings can mean either copying the reference (two variables refer to the same instance) or creating a distinct string object with the same contents. This question targets creating a separate string instance with identical content. Given Data / Assumptions: We want to 'copy the contents' of one string into another. Options include assignment, String.Concat, String.Copy, and invalid usages. Concept / Approach: Assignment (s2 = s1) copies the reference, not the object; both variables point to the same immutable instance. String.Copy(s1) historically created a new string instance with the same content (note: it is obsolete in newer .NET, but within classic C#.NET contexts, it denotes a content copy). Concat concatenates and does not copy content alone. Replace() without arguments is invalid, and StringCopy is not an API. Step-by-Step Solution: Option A: Reference copy only (same instance) → not a distinct content copy.Option B: Concatenates s1 and s2 (undefined s2 content) → incorrect.Option C: String.Copy(s1) → creates a new string with the same contents.Option D: Invalid method usage.Option E: Nonexistent method. Verification / Alternative check: Another way to ensure a distinct instance is new string(s1.ToCharArray()), though rarely necessary. Since strings are immutable, reference sharing is usually safe. Why Other Options Are Wrong: They either do not produce a new object with the same contents or call invalid/nonexistent APIs. Common Pitfalls: Assuming assignment duplicates the object; in .NET it only assigns the reference. Final Answer: String s1 = 'String'; 
String s2;
s2 = String.Copy(s1);

Question 11

C#.NET — What does this program print? namespace CuriousTabConsoleApplication { class SampleProgram { static void Main(string[] args) { string str = "Hello World!"; Console.WriteLine(String.Compare(str, "Hello World?").GetType()); } } } Predict the …

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Introduction / Context: This C#.NET snippet tests understanding of return types, boxing of value types, and how Console.WriteLine formats objects. Specifically, it explores what happens when you call GetType() on the result of String.Compare. Given Data / Assumptions: String.Compare(string, string) returns an int (-1, 0, or 1 depending on ordering). GetType() is available on all objects and value types (via boxing semantics and methods defined on System.ValueType). Console.WriteLine calls ToString() on the object it receives. Concept / Approach: String.Compare(str, "Hello World?") produces an integer. Calling GetType() on an int yields a System.Type object that represents the type of the value, namely System.Int32. Printing a Type using WriteLine invokes its ToString(), which returns the fully qualified type name. Step-by-Step Solution: Compute comparison → some integer (the actual numeric value is irrelevant to the output).Call GetType() on that integer → returns a Type representing System.Int32.Print the Type → outputs the string System.Int32. Verification / Alternative check: Replace the call with Console.WriteLine(typeof(int)); the output is also System.Int32, confirming the behavior. Why Other Options Are Wrong: 0 or 1 are possible compare results but not what gets printed. String and Hello World? are not the Type name. The exact printed value is the fully qualified type name. Common Pitfalls: Confusing the comparison result with the printed type, or assuming GetType() is unavailable on value types. Final Answer: System.Int32

Question 12

C#.NET — Which is the correct way to find the index of the second 's' in the string: "She sells sea shells on the sea-shore"? Choose the valid code snippet that correctly identifies the second occurrence.

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Introduction / Context: Locating the second occurrence of a character in a string is a standard string manipulation problem. In C#.NET, the IndexOf method is heavily used to search for substrings or characters, and it has an overload that accepts a starting index. This makes it possible to find subsequent occurrences of a character. Given Data / Assumptions: We are working with the string "She sells sea shells on the sea-shore". We want the index of the second lowercase 's'. The operation must be case-sensitive; uppercase S at the beginning is not the same as lowercase 's'. Concept / Approach: The proper approach is to find the first occurrence using IndexOf("s"). Then, to locate the second occurrence, use the overload IndexOf("s", i + 1), which searches the string starting from the next index position after the first match. Step-by-Step Solution: i = str.IndexOf("s"); → returns the first index of lowercase s.j = str.IndexOf("s", i + 1); → continues the search after the first match to find the second occurrence.The variable j now holds the index of the second s. Verification / Alternative check: A manual scan of the string shows lowercase s at positions 6 (in "sells") and 10 (in "sea"). The code correctly returns index 10 for the second occurrence. Why Other Options Are Wrong: (a) SecondIndexOf does not exist in .NET. (b) FirstIndexOf is not a valid method. (d) LastIndexOf finds the last occurrence, not the second. (e) Mixing uppercase and lowercase S incorrectly addresses the wrong character. Common Pitfalls: Forgetting that strings are zero-indexed or confusing uppercase and lowercase letters. Another frequent mistake is not incrementing the start index, which would simply return the same first occurrence again. Final Answer: String str = "She sells sea shells on the sea-shore"; int i, j; i = str.IndexOf("s"); j = str.IndexOf("s", i + 1);

Question 13

C#.NET strings — identify the correct statements about string type, literals, equality, bounds, and mutability.

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Introduction / Context: Immutable strings are fundamental in .NET. This item checks knowledge of string type (reference vs value), literal rules, equality operator behavior, bounds checking, and whether contents can change after creation. Given Data / Assumptions: Five statements about strings are presented; select all true ones. C# string is an alias for System.String. Concept / Approach: Evaluate each claim against .NET semantics: immutability, operator overloading for equality, and runtime exceptions on invalid indexing. Step-by-Step Solution: 1) “String is a value type.” → False. It is a reference type.2) “String literals can contain escape sequences.” → True. Examples include "Hello
World" or verbatim strings @""C:	emp"".3) “Equality operators compare values as well as references.” → False. == for string is overloaded to compare values (contents), not reference identity.4) “Out-of-bounds character access throws IndexOutOfRangeException.” → True for string indexer.5) “String contents can be changed after creation.” → False. Strings are immutable; use StringBuilder for in-place-like edits. Verification / Alternative check: Test object.ReferenceEquals(s1, s2) vs s1 == s2 to see value vs reference behavior; try s[9999] to observe the exception. Why Other Options Are Wrong: Any option containing 1, 3, or 5 is invalid due to the reasons above. Common Pitfalls: Confusing string interning (which can make references equal) with the semantics of ==, which compares contents. Final Answer: 2, 4

Question 14

C#.NET — choose the valid ways to convert a Single (float) to a String.

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Introduction / Context: Converting numeric types to strings is routine in C#.NET. The question presents several code snippets and asks which are valid for converting a Single (alias float) into a String. Given Data / Assumptions: Single f = 9.8f; then assign a string variable s. Snippets may include syntax from other languages or invalid casts. Concept / Approach: In C#, use Convert.ToString or the instance ToString() method. Direct casting from float to string is illegal, and VB-specific functions like CString or Clnt do not exist in C#. Step-by-Step Solution: Valid: s = Convert.ToString(f); → uses framework converter.Valid: s = f.ToString(); → instance method on value type.Invalid: (String)(f) → no direct cast defined.Invalid: Clnt and CString → VB-style; not C# identifiers. Verification / Alternative check: Try formatting: f.ToString("F2") for 2 decimal places, demonstrating rich formatting support. Why Other Options Are Wrong: They are either syntactically invalid in C# or rely on non-existent conversion helpers. Common Pitfalls: Assuming a C-style cast will work for disparate types like float to string. Final Answer: s = Convert.ToString(f); (also acceptable: s = f.ToString();)

Question 15

C#.NET strings — select the correct statement about strings.

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Introduction / Context: This item focuses on core properties of C# strings: immutability, indexing, and representation. Given Data / Assumptions: We are evaluating stand-alone statements regarding strings. Concept / Approach: In C#, string is immutable and zero-indexed. You can create new strings via methods, but existing instances do not change in place. Step-by-Step Solution: Immutability: statements (a) and (b) are false; methods return new strings instead of modifying the original.Numeric text: (c) is false; any number can be represented as text (e.g., "123").Indexing: (d) is true — string indexer uses zero-based positions.Representation: (e) is false — strings are System.String, not System.Array, though you can get a char[] copy. Verification / Alternative check: Observe that s.Replace("a","b") leaves s unchanged and returns a new string. Why Other Options Are Wrong: They contradict immutability or conflate arrays with strings. Common Pitfalls: Assuming string behaves like a mutable character buffer; use StringBuilder for that. Final Answer: A String has a zero-based index.

Question 16

C#.NET strings — evaluate the output of: String s1 = "ALL MEN ARE CREATED EQUAL"; String s2; s2 = s1.Substring(12, 3); Console.WriteLine(s2);

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Introduction / Context: This tests correct use of Substring(startIndex, length) with zero-based indexing. Given Data / Assumptions: s1 = "ALL MEN ARE CREATED EQUAL" startIndex = 12, length = 3 Concept / Approach: Substring takes characters starting at startIndex and returns exactly length characters. Indexes are zero-based and include spaces as characters. Step-by-Step Solution: Enumerate indices: 0 A, 1 L, 2 L, 3 space, 4 M, 5 E, 6 N, 7 space, 8 A, 9 R, 10 E, 11 space, 12 C, 13 R, 14 E, ...Starting at 12 for 3 characters → "C", "R", "E" → "CRE". Verification / Alternative check: Print s1[12], s1[13], s1[14] to confirm characters. Why Other Options Are Wrong: ARE or REA correspond to other ranges; CREATED is too long. Common Pitfalls: Off-by-one errors or forgetting spaces count toward indices. Final Answer: CRE

Question 17

C#.NET — Determine the correct output for the code: String s1 = "Kicit"; Console.Write(s1.IndexOf('c') + " "); Console.Write(s1.Length);

Accepted Answer

Introduction / Context: This program evaluates two string operations: finding the index of a character and retrieving the length of the string. It checks whether the learner understands zero-based indexing in C#.NET strings and how IndexOf works. Given Data / Assumptions: s1 = "Kicit" Method call: s1.IndexOf('c') Property: s1.Length Concept / Approach: Strings in C# are zero-based, meaning the first character is at index 0. IndexOf returns the index of the first occurrence of a given character or substring. Length returns the number of characters in the string. Step-by-Step Solution: Characters with indices: 0 → K, 1 → i, 2 → c, 3 → i, 4 → tIndexOf('c') = 2 because c appears at index 2.Length = 5 because there are five characters total.The program prints: "2 5". Verification / Alternative check: Test in a C# REPL or Visual Studio project confirms IndexOf('c') == 2 and Length == 5. Output matches expectation. Why Other Options Are Wrong: (a) and (c) suggest incorrect index or length. (d) assumes length 6, which is wrong. (e) assumes 7, which is also wrong. Common Pitfalls: Counting indices from 1 instead of 0 or mistaking Length as the last index rather than number of elements. Final Answer: 2 5

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