What will be the output of the program assuming that the array begins at the location 1002 and size of an integer is 4 bytes? #include int main() { int a[3][4] = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12 }; printf("%u, %u, %u "…

Question

What will be the output of the program assuming that the array begins at the location 1002 and size of an integer is 4 bytes? #include<stdio.h>

int main()
{
    int a[3][4] = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12 };
    printf("%u, %u, %u
"…

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What will be the output of the program assuming that the array begins at the location 1002 and size of an integer is 4 bytes? #include<stdio.h> int main() { int a[3][4] = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12 }; printf("%u, %u, %u\n", a[0]+1, (a[0]+1), (*(a+0)+1)); return 0; }

Discussion & Comments

What will be the output of the program assuming that the array begins at the location 1002 and size of an integer is 4 bytes? #include<stdio.h> int main() { int a[3][4] = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12 }; printf("%u, %u, %u\n", a[0]+1, *(a[0]+1), *(*(a+0)+1)); return 0; }

Discussion & Comments

What will be the output of the program assuming that the array begins at the location 1002 and size of an integer is 4 bytes? #include<stdio.h> int main() { int a[3][4] = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12 }; printf("%u, %u, %u\n", a[0]+1, (a[0]+1), (*(a+0)+1)); return 0; }