Simple Interest — Borrow low, lend high arbitrage: Prabhat borrows at 8% p.a. SI and lends the same sum to Ashish at 12% p.a. SI. If his profit in 2 years is Rs 320, how much did he borrow?

Difficulty: Easy

Correct Answer: Rs. 4000

Explanation:


Introduction / Context:
Arbitrage under SI arises from lending at a higher rate than the borrowing rate. The net gain equals principal times the rate spread times time.



Given Data / Assumptions:

  • Borrowing rate = 8% p.a.
  • Lending rate = 12% p.a.
  • Time = 2 years
  • Profit = Rs 320


Concept / Approach:
Profit = P * (rate spread) * t = P * (0.12 − 0.08) * 2 = 0.08 * P. Solve 0.08 * P = 320 for P.



Step-by-Step Solution:

0.08 * P = 320 ⇒ P = 320 / 0.08 = Rs 4000.


Verification / Alternative check:

Interest received = 4000 * 12% * 2 = 960; paid = 4000 * 8% * 2 = 640; profit = 320 (matches).


Why Other Options Are Wrong:

  • 2000, 3000, 5000, 6000 do not yield a spread-based profit of 320 over 2 years.


Common Pitfalls:

  • Using 12% − 8% = 2% instead of 4%; the spread is 4% per annum.


Final Answer:
Rs 4000.

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