Simple Interest — Reverse present worth via SI discounting: A person closes an investment by withdrawing ₹ 10000 today, ₹ 6000 one year ago, and ₹ 5000 two years ago. Three years ago there was no withdrawal. Assuming 10% p.a. simple interest since opening, what was the approximate initial deposit 4 years ago?

Difficulty: Hard

Correct Answer: ₹ 15600

Explanation:


Introduction / Context:
With simple interest, the present worth of withdrawals at different times (counted from opening) uses linear discounting: PV at opening = Withdrawal / (1 + r * t). Summing the present worths of all withdrawals reconstructs the initial deposit, assuming the scheme accrued SI uniformly from the opening on the original principal.



Given Data / Assumptions:

  • Annual simple interest r = 10% = 0.10
  • Opening was 4 years ago
  • Withdrawals: ₹ 5000 at t = 2 years, ₹ 6000 at t = 3 years, ₹ 10000 at t = 4 years
  • Goal: approximate initial deposit (no other cash flows)


Concept / Approach:
Under SI, accumulation to a future date uses A = P * (1 + r * t). Conversely, discounting a known future amount W back to opening uses PV = W / (1 + r * t). The initial principal is the sum of the PVs of all withdrawals.



Step-by-Step Solution:

PV(₹ 5000 at t = 2) = 5000 / (1 + 0.10 * 2) = 5000 / 1.20 ≈ 4166.67PV(₹ 6000 at t = 3) = 6000 / (1 + 0.10 * 3) = 6000 / 1.30 ≈ 4615.38PV(₹ 10000 at t = 4) = 10000 / (1 + 0.10 * 4) = 10000 / 1.40 ≈ 7142.86Initial deposit ≈ 4166.67 + 4615.38 + 7142.86 ≈ ₹ 15924.91.


Verification / Alternative check:

Rounding to the nearest option, ₹ 15600 is closest (diff ≈ ₹ 325), consistent with “approximately”.


Why Other Options Are Wrong:

  • ₹ 16500 and ₹ 17280 deviate farther from the computed present worth.
  • ₹ 15000 underestimates the required initial deposit.


Common Pitfalls:

  • Using compound discounting; SI requires linear discount factors 1 + r * t.
  • Mistiming the withdrawals (ensure t = 2, 3, 4 from opening).


Final Answer:
Approximately ₹ 15600.

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