Difficulty: Hard
Correct Answer: ₹ 120 and 66 2/3 yr
Explanation:
Introduction / Context:Two simple-interest amounts with the same time but different rates provide two linear equations in principal P and time t. Solving them simultaneously yields both the initial sum and the duration, even when the time is unusually long.
Given Data / Assumptions:
Concept / Approach:Divide equations or subtract to eliminate P or t. One direct approach is to solve as a 2×2 system for P and t in real numbers under SI linearity.
Step-by-Step Solution:
From A2: P = 200 / (1 + 0.01 t).Substitute in A1: 200 * (1 + 0.06 t) / (1 + 0.01 t) = 600 ⇒ (1 + 0.06 t) / (1 + 0.01 t) = 3.Cross-multiply: 1 + 0.06 t = 3 + 0.03 t ⇒ 0.03 t = 2 ⇒ t = 66.666... years.Then P = 200 / (1 + 0.6666...) = 200 / 1.6666... = ₹ 120.Verification / Alternative check:
Check A1: 120 * (1 + 0.06 * 66.666...) = 120 * 5 = 600; A2: 120 * (1 + 0.01 * 66.666...) = 120 * 1.6666... = 200.Why Other Options Are Wrong:
Common Pitfalls:
Final Answer:₹ 120 and 66 2/3 years.
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