Simple Interest — Mixed fractions of a fund at different rates: One-third of a sum is at 3% p.a., one-sixth at 6% p.a., and the rest at 8% p.a. If total SI for 2 years is ₹ 600, find the original sum.

Difficulty: Easy

Correct Answer: ₹ 5000

Explanation:


Introduction / Context:
This is a weighted-average SI problem across sub-parts of one principal. Each fraction contributes SI proportional to its share, rate, and time; the total is the sum of these contributions over 2 years.



Given Data / Assumptions:

  • Total principal S (unknown)
  • 1/3 at 3% p.a.; 1/6 at 6% p.a.; remainder at 8% p.a.
  • Time = 2 years; total SI = ₹ 600


Concept / Approach:
Total SI = S * [ (1/3)*0.03*2 + (1/6)*0.06*2 + (1 − 1/3 − 1/6)*0.08*2 ]. Evaluate the bracket and equate to 600 to solve for S.



Step-by-Step Solution:

Bracket = (1/3)*0.06 + (1/6)*0.12 + (1/2)*0.16 = 0.02 + 0.02 + 0.08 = 0.12.0.12 * S = 600 ⇒ S = 600 / 0.12 = ₹ 5000.


Verification / Alternative check:

Compute SI parts on ₹ 5000: 5000*(1/3)*0.03*2 = 100; 5000*(1/6)*0.06*2 = 100; 5000*(1/2)*0.08*2 = 400; total = 600.


Why Other Options Are Wrong:

  • Other sums do not satisfy the 0.12 * S = 600 condition.


Common Pitfalls:

  • Forgetting that the leftover fraction is 1 − 1/3 − 1/6 = 1/2.


Final Answer:
₹ 5000.

More Questions from Simple Interest

Discussion & Comments

No comments yet. Be the first to comment!
Join Discussion