Difficulty: Easy
Correct Answer: ₹ 5000
Explanation:
Introduction / Context:This is a weighted-average SI problem across sub-parts of one principal. Each fraction contributes SI proportional to its share, rate, and time; the total is the sum of these contributions over 2 years.
Given Data / Assumptions:
Concept / Approach:Total SI = S * [ (1/3)*0.03*2 + (1/6)*0.06*2 + (1 − 1/3 − 1/6)*0.08*2 ]. Evaluate the bracket and equate to 600 to solve for S.
Step-by-Step Solution:
Bracket = (1/3)*0.06 + (1/6)*0.12 + (1/2)*0.16 = 0.02 + 0.02 + 0.08 = 0.12.0.12 * S = 600 ⇒ S = 600 / 0.12 = ₹ 5000.Verification / Alternative check:
Compute SI parts on ₹ 5000: 5000*(1/3)*0.03*2 = 100; 5000*(1/6)*0.06*2 = 100; 5000*(1/2)*0.08*2 = 400; total = 600.Why Other Options Are Wrong:
Common Pitfalls:
Final Answer:₹ 5000.
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