BJT saturation indicator: Approximately what is VCE when a silicon transistor is driven into saturation?

Difficulty: Easy

Correct Answer: About 0.2 V

Explanation:


Introduction / Context:
Recognizing saturation is vital in switching applications. When a BJT saturates, both junctions are forward biased and the collector-emitter voltage collapses to a small value, which sets the lower bound of the output low level and affects power dissipation.


Given Data / Assumptions:

  • Silicon BJT used as a switch.
  • Heavy base drive sufficient to enter saturation.
  • Typical room-temperature operation.


Concept / Approach:
In saturation, VBE is forward biased (around 0.7–0.9 V) and VBC is also forward biased. The collector-emitter path behaves like a low-resistance segment, and VCE(sat) is typically small, often quoted near 0.2 V for small-signal devices (exact value depends on current and device type).


Step-by-Step Solution:

Drive the base strongly so the collector current is limited by the load, not beta.Both junctions forward bias; the transistor leaves the active region.Observe VCE(sat) collapsing to a small residual voltage, about 0.2 V for many devices.


Verification / Alternative check:
Consult datasheets: VCE(sat) is specified versus IC and IB, often 0.05–0.3 V for small-signal BJTs. Power devices may exhibit higher values, but 0.2 V remains a common nominal figure.


Why Other Options Are Wrong:

  • VCC (option a) is the supply, not the drop in saturation.
  • VB (option b) refers to base potential, not the collector-emitter drop.
  • 0.7 V (option d) is characteristic of a base-emitter junction, not VCE(sat).


Common Pitfalls:
Confusing VCE(sat) with VBE or assuming a fixed 0.2 V across all currents and devices; the value varies but remains “small.”


Final Answer:
About 0.2 V.

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