Difficulty: Easy
Correct Answer: gm (transconductance of the MOSFET)
Explanation:
Introduction / Context:
The common-source (CS) MOSFET amplifier is a foundational gain stage in analog electronics. Its midband small-signal voltage gain primarily depends on device transconductance and the effective load seen at the drain. This question probes your understanding of which parameter most directly scales the small-signal voltage gain when the circuit is otherwise biased and loaded consistently.
Given Data / Assumptions:
Concept / Approach:
For a CS stage without source degeneration, the approximate gain is Av ≈ −gm * (RD || RL). With an unbypassed source resistor, Av ≈ −(gm * (RD || RL)) / (1 + gm * RS). In both forms, gm appears as a direct multiplicative factor that scales the magnitude of Av. Changing gm directly alters how much output voltage develops per unit input small-signal gate voltage.
Step-by-Step Solution:
Verification / Alternative check:
If RD or RL is fixed, doubling gm roughly doubles |Av| (ignoring degeneration). Conversely, halving gm halves |Av|. Supply voltage VDD influences bias headroom but does not directly multiply the small-signal gain unless it shifts the operating point and thereby changes gm indirectly.
Why Other Options Are Wrong:
Common Pitfalls:
Confusing amplitude with gain, or assuming VDD directly sets gain. Remember that in midband small-signal analysis, gm and the effective load dominate voltage gain.
Final Answer:
gm (transconductance of the MOSFET)
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