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Binary addition check: Compute 0101 + 1111 and evaluate the proposed result 10100.

Difficulty: Easy

Correct Answer: Correct

Explanation:


Introduction / Context:
This verifies a straightforward binary addition. We add 0101 (5) to 1111 (15) and check whether the sum equals 10100 (20).


Given Data / Assumptions:

  • Operands are unsigned binary vectors.
  • No fixed word-size truncation is imposed.


Concept / Approach:
Binary addition proceeds bitwise with carries. If the result exceeds the current word width, we extend the width to include the final carry, producing a wider sum.


Step-by-Step Solution:

LSB: 1 + 1 = 0, carry 1.Next: 0 + 1 + carry 1 = 0, carry 1.Next: 1 + 1 + carry 1 = 1, carry 1.MSB: 0 + 1 + carry 1 = 0, carry 1 → write final carry as new MSB.Result: 10100 (decimal 20).


Verification / Alternative check:
Decimal check: 5 + 15 = 20 → binary 10100.


Why Other Options Are Wrong:

Incorrect: Contradicts standard addition.Saturation/word-size ambiguity: Only relevant if a fixed 4-bit result is required; with natural-width arithmetic, 5-bit result is correct.BCD correction: Not applicable; operands are pure binary, not BCD.


Common Pitfalls:
Forgetting to emit the final carry as the new MSB.


Final Answer:
Correct

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