Difficulty: Easy
Correct Answer: Both A and R are true and R is correct explanation of A
Explanation:
Introduction / Context:
Carrier transport under an applied electric field is a cornerstone of electronic device physics. The concepts of drift velocity and mobility appear in conductivity, Ohm’s law at the microscopic level, and current–voltage characteristics of semiconductors and metals.
Given Data / Assumptions:
Concept / Approach:
In the low-field regime, v_d = μ E, where v_d is drift velocity and μ is mobility. Thus v_d ∝ E, and μ ≡ v_d / E. This linearity breaks down only at very high fields (velocity saturation, hot-carrier effects), but for ordinary operation the proportionality is valid and mobility provides the constant of proportionality.
Step-by-Step Solution:
Verification / Alternative check:
Conductivity σ = q n μ in semiconductors (or σ = q p μ_p for holes) connects mobility to measurable current density J = σ E, reinforcing the proportional relationship.
Why Other Options Are Wrong:
Claiming the statements are false contradicts basic transport models; denying the explanatory role of mobility ignores the definition μ = v_d / E.
Common Pitfalls:
Extending linearity into high-field regimes without accounting for velocity saturation; confusing thermal velocity with drift velocity.
Final Answer:
Both A and R are true and R is correct explanation of A
Discussion & Comments