In a semiconductor, the probability of electron–hole recombination is proportional to which carrier measure? Choose the best expression for how recombination rate depends on carrier concentrations.

Difficulty: Easy

Correct Answer: Product of electron and hole densities (n * p)

Explanation:


Introduction / Context:
Carrier recombination is central to semiconductor devices (diodes, LEDs, solar cells). The rate at which electrons and holes annihilate each other determines lifetime, minority-carrier dynamics, and device efficiency. A basic qualitative rule is that recombination requires both species to be present: electrons and holes must meet to recombine.


Given Data / Assumptions:

  • Uniform semiconductor material at steady conditions.
  • Nonradiative and radiative recombination mechanisms are possible.
  • We focus on the basic concentration dependence.


Concept / Approach:

In its simplest form, the recombination rate R is proportional to the probability of an electron meeting a hole, which scales with the product of their concentrations, n and p. Many models express this as R ∝ n p − ni^2 under nonequilibrium conditions, where ni is the intrinsic concentration. Thus, higher density of either species alone is not sufficient; both must be present for recombination events to occur.


Step-by-Step Solution:

Recognize recombination requires an electron and a hole simultaneously.Meeting probability ∝ n * p under well-mixed conditions.Therefore, select the dependence on the product n * p.


Verification / Alternative check:

Device equations (e.g., low-level injection in p–n junctions) commonly use recombination terms proportional to n p − ni^2 with appropriate coefficients for SRH, radiative, or Auger processes, reinforcing the product dependence.


Why Other Options Are Wrong:

  • Electrons only or holes only: ignores the need for the other carrier.
  • Sum (n + p): does not represent pairwise interaction probabilities.
  • None of the above: incorrect because n * p dependence is well-established.


Common Pitfalls:

Assuming linear dependence on a single carrier or forgetting the equilibrium correction term n p ≈ ni^2 in intrinsic conditions.


Final Answer:

Product of electron and hole densities (n * p)

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