In a semiconductor, the probability of electron–hole recombination is proportional to which carrier measure? Choose the best expression for how recombination rate depends on carrier concentrations.
-
ADensity of electrons only
-
BDensity of holes only
-
CProduct of electron and hole densities (n * p)
-
DNone of the above
-
ESum of electron and hole densities (n + p)
Answer
Correct Answer: Product of electron and hole densities (n * p)
Explanation
Introduction / Context:Carrier recombination is central to semiconductor devices (diodes, LEDs, solar cells). The rate at which electrons and holes annihilate each other determines lifetime, minority-carrier dynamics, and device efficiency. A basic qualitative rule is that recombination requires both species to be present: electrons and holes must meet to recombine.
Given Data / Assumptions:
- Uniform semiconductor material at steady conditions.
- Nonradiative and radiative recombination mechanisms are possible.
- We focus on the basic concentration dependence.
Concept / Approach:
In its simplest form, the recombination rate R is proportional to the probability of an electron meeting a hole, which scales with the product of their concentrations, n and p. Many models express this as R ∝ n p − ni^2 under nonequilibrium conditions, where ni is the intrinsic concentration. Thus, higher density of either species alone is not sufficient; both must be present for recombination events to occur.
Step-by-Step Solution:
Recognize recombination requires an electron and a hole simultaneously.Meeting probability ∝ n * p under well-mixed conditions.Therefore, select the dependence on the product n * p.Verification / Alternative check:
Device equations (e.g., low-level injection in p–n junctions) commonly use recombination terms proportional to n p − ni^2 with appropriate coefficients for SRH, radiative, or Auger processes, reinforcing the product dependence.
Why Other Options Are Wrong:
- Electrons only or holes only: ignores the need for the other carrier.
- Sum (n + p): does not represent pairwise interaction probabilities.
- None of the above: incorrect because n * p dependence is well-established.
Common Pitfalls:
Assuming linear dependence on a single carrier or forgetting the equilibrium correction term n p ≈ ni^2 in intrinsic conditions.
Final Answer:
Product of electron and hole densities (n * p)