Permittivity units and constitutive relation Assertion (A): The permittivity of free space ε0 has the dimensions of farad per metre (F/m). Reason (R): The electric flux density satisfies D = ε0 εr E, where εr is dimensionless relative permittivity and E is the electric field.
-
ABoth A and R are true and R is correct explanation of A
-
BBoth A and R are true but R is not correct explanation of A
-
CA is true but R is false
-
DA is false but R is true
-
EBoth A and R are false
Answer
Correct Answer: Both A and R are true and R is correct explanation of A
Explanation
Introduction / Context:Permittivity connects electric field E to electric flux density D. Correct unit analysis is vital in electromagnetics, dielectric design, and capacitor calculations. This item tests whether the constitutive equation explains the dimensionality of ε0.
Given Data / Assumptions:
- D = ε0 εr E in linear, isotropic media.
- εr is dimensionless; ε0 carries the physical units.
- Standard SI base units are used for dimensional analysis.
Concept / Approach:
From D = ε E in vacuum (ε = ε0), the units must satisfy [D] = [ε0][E]. Using SI, [D] = C/m^2 and [E] = V/m. Therefore [ε0] = (C/m^2) / (V/m) = C/(V·m) = F/m, because 1 F = C/V. Hence the constitutive relation directly explains the unit of ε0.
Step-by-Step Solution:
Write D = ε0 εr E; set εr = 1 for free space.Units: [D] = C/m^2, [E] = V/m.Compute [ε0] = (C/m^2) / (V/m) = C/(V·m) = F/m.Verification / Alternative check:
Capacitance per unit length of a parallel-plate capacitor in vacuum, C = ε0 A/d, also yields [ε0] = F/m when solving for units.
Why Other Options Are Wrong:
Any option denying the equation or the dimensional derivation conflicts with standard SI definitions and Maxwell’s equations.
Common Pitfalls:
Confusing ε0 (F/m) with εr (dimensionless), or mixing Gaussian and SI unit systems.
Final Answer:
Both A and R are true and R is correct explanation of A