A can finish a work in 18 days and B can do the same work in 15 days. B worked for 10 days and left the job. In how many days, A alone can finish the remaining work?

5
5 1 2
6
8

Correct Answer: 6

Explanation:

B's 10 day's work =	❨	1	x 10	❩	=	2	.
		15				3

Remaining work =	❨	1 -	2	❩	=	1	.
			3			3

Now,	1	work is done by A in 1 day.
	18

∴	1	work is done by A in	❨	18 x	1	❩	= 6 days.
	3				3

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