A and B together can do a piece of work in 30 days. A having worked for 16 days, B finishes the remaining work alone in 44 days. In how many days shall B finish the whole work alone?
Correct Answer: 60 days
Explanation:
Let A's 1 day's work = x and B's 1 day's work = y.
Then, x + y =
1
and 16x + 44y = 1.
30
Solving these two equations, we get: x =
1
and y =
1
60
60
∴ B's 1 day's work =
1
.
60
Hence, B alone shall finish the whole work in 60 days.
