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A and B together can do a piece of work in 30 days. A having worked for 16 days, B finishes the remaining work alone in 44 days. In how many days shall B finish the whole work alone?

Correct Answer: 60 days

Explanation:

Let A's 1 day's work = x and B's 1 day's work = y.



Then, x + y = 1 and 16x + 44y = 1.
30



Solving these two equations, we get: x = 1 and y = 1
60 60



∴ B's 1 day's work = 1 .
60


Hence, B alone shall finish the whole work in 60 days.


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