More Questions from Problems on H.C.F and L.C.M

Compute the HCF using prime factorizations quickly Find the highest common factor (HCF) of 1485 and 4356.

Aptitude Problems on H.C.F and L.C.M Difficulty: Easy
Choose an option
  • A
    189
  • B
    89
  • C
    99
  • D
    83
  • E
    27

Answer

Correct Answer: 99

Explanation

Introduction / Context:HCF (gcd) between two integers is easiest via either the Euclidean algorithm or prime factorisation. Recognising square structures can speed factorisation substantially.

Given Data / Assumptions:

  • Numbers: 1485 and 4356.
  • We aim to find gcd(1485, 4356).

Concept / Approach:Factor both: 1485 ends with 5, so divisible by 5; 4356 is 4 * 1089 and 1089 is 33^2, which is 3^2 * 11^2. Take minimum exponents for common primes.

Step-by-Step Solution:1485 = 5 * 297 = 5 * (27 * 11) = 3^3 * 5 * 11.4356 = 4 * 1089 = 2^2 * (33^2) = 2^2 * 3^2 * 11^2.Common primes: 3 and 11. Minimum exponents: 3^2 and 11^1.Therefore HCF = 3^2 * 11 = 9 * 11 = 99.

Verification / Alternative check:Divide: 1485 ÷ 99 = 15; 4356 ÷ 99 = 44. Both are integers, confirming gcd = 99.

Why Other Options Are Wrong:189 = 9 * 21 includes factor 7 (not common); 89 and 83 are primes that do not divide 1485; 27 divides 1485 but not 4356 exactly.

Common Pitfalls:Stopping after finding a small common factor like 3 or 11; forgetting to include both common primes at their minimum exponents.

Final Answer:99

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