Question 1

The price of rice is reduced by 5%. How many kilograms of rice can now be bought for the money, which was sufficient to buy 50 kg of rice earlier?

Accepted Answer

Let original price be ₹ 100 per kg. Money required to buy 50 kg of rice = ₹ (100 x 50) = ₹ 5000 New price = (100 - 5) = ₹ 95 per kg ∴ Quantity of rice bought = (5000/95) kg = 52.63 kg

Question 2

Due to a 25% increased in the price of rice per kilogram, a person is able to purchase 20 kg less for ₹ 400. What is the increased price of rice per kilogram?

Accepted Answer

Increase in the price of rice = 25% ∴ increased in ₹ 400 = 25% of ₹ 400 = 400 x (25/100) = ₹ 100 ∵ Increased in rate of rice in 25%, there are 20kg less rice in ₹ 400 i.e., rate of 20 kg rice = ₹ 100 = Rate of 1kg rice = 100/20 = ₹ 5 ∴ Increased price of rice = ₹ 5 per kg

Question 3

In a class of 40 students and 5 teachers, each student got sweets that are 15% of the total number of students and each teacher got sweets that are 20% of the total number of the students. How many sweets were there?

Accepted Answer

Number of sweets received by every students = 15% of 40 = (40 x 15)/100 = 6 ∴ Number of sweets received by 40 students = 40 x 6 = 240 Number of sweets received by each teacher = 20% of 40 = (40 x 20)/100 = 8 ∴ Number of sweets received by 5 teachers = 8 x 5 = 40 ∴ Total number of sweets = 240 + 40 = 280

Question 4

Fresh grapes contain 80% water, while dry grapes contain 10% water. If the weight of dry grapes is 500 kg, then what is its total weight when it is fresh?

Accepted Answer

Let the weight of fresh grapes be W. Quantity of water in it = (80/100) x W = 4W/5 Quantity of pulp in it = W - (4W/5) = W/5 Quantity of water in 500 gm dry grapes = (10/100) x 500 = 50 kg ∴ Quantity of pulp in it = (500 -50) = 450 kg W/5 = 450 ∴ W = 2250 kg

Question 5

The price of rice decreased by 6.25% and because of this reduction. Vandana is able to buy 1 kg more for ₹120. Find the reduce rate of rice.

Accepted Answer

Let original rate of rice be ₹ x per kg Reduced rate = ₹ [(100 - 6.25) x (1/100) x W] = ₹ 15W/16 per kg According to the question 120/(15W/16) - 120/W = 1 ⇒ (120 x 16)/15W - 120/W = 1 ⇒ 120 x 16 - 1800 = 15W ⇒ 128 - 120 = W ∴ W = ₹ 8 per kg. ∴ Reduced rate = ₹ (15/16) x 8 per kg =₹ 7.50 per kg

Question 6

Wheat is now being sold at ₹ 27 per kg. During last month, its cost was ₹ 24 per kg. Find by how much per cent a family reduced its consumption, so as to keep the expenditure fixed.

Accepted Answer

Old price of rice = ₹ 24/kg New price of rice = ₹ 27 per/Kg ∴ increased in price of rice = New price - Old prices = 27 - 24 = ₹ 3/kg ∴ increased percentage in price = (3/24) x 100 = 121/2 % Now, reduction in consumption, so as to keep the expenditure fixed. According to the formula, = [a/(100 + a)] x 100 % =[1.25/(100 +12.5)] x 100% = 11.1%

Question 7

A marketing manager is able to manage an average of Rs240 per week during 40h week . But in the final week of the month, his rates are increased by 50%. Then find out the commission the marketing manager makes in that week, if he puts in 60h during …

Accepted Answer

Average rate per hr = 240/40 = Rs6/hr In last week, his rate per hour increases by 50%, so in the last week, his hourly rate = Rs.6 x (1+50%)= Rs.9 Total hour spent in final week = 60h ∴ Total commission = 60h x Rs.9/hr = Rs.540

Question 8

A candidate attempted 12 questions and secured full marks in all of them. If he obtained 60% in the test and each questions carried equal marks, then what was the total number of questions in the test?

Accepted Answer

Let the number of question be Y. 60% of Y = 12 60Y / 100 =12 Y = 20

Question 9

Pradeep spends 40 percent of his monthly income on food items and 50 percent of the remaining, on cloths and conveyance. He saves one-third of the remaining amount after spending on food, clothes and conveyance. If he saves Rs.19,200 every year, wha…

Accepted Answer

From question, Food items = 40% Clothes + conveyance = 50% of 60% = 30% ⇒ Remaining amount = (100 - 40 - 30)% = 30% ∴ 1/3 of 30% = 19200 ⇒ 10% = 19200 ∴ 100% = Rs. 192000 So his monthly income = 192000 / 12 = 16000

Question 10

Ashok gave 40 per cent of the amount he had to Jayant. Jayant in turn gave one-fourth of what he receive from Ashok to Prakash. After paying Rs. 200 to the taxi driver out of the amount he got from Jayant,Prakash now has Rs. 600 left with him.How mu…

Accepted Answer

∵ J = 40% of A =2A/5 ⇒ P = 1/4 x 2A/5 = A/10 ⇒ A/10 - 200 = 600 ⇒ A/10 = 800 ∴ A = Rs. 8000

Question 11

Rajesh solved 80 percent of the questions in an examination correctly, out of 41 questions solved by Rajesh 37 questions are correct and of the remaining questions out of 8 questions, 5 questions have been solved by Rajesh correctly then find the to…

Accepted Answer

Suppose there are 8y questions were asked apart from the 41 question.Then 37 + 5y/41 + 8y = 80% = 4/5 ⇒ 185 + 25y = 164 + 32y ⇒ 7y = 21 ⇒ y = 3 ∴ Total no. of questions = 41 + 8 x 3 = 65.

Question 12

In a class of 60 children 30% children can speak only English, 20% Hindi and English both and the rest of the children can speak only Hindi. How many children can speak Hindi?

Accepted Answer

Number of student who speak only English =30% of 60 = 18 Number of student who speak Hindi and English =20% of 60 =12 ∴Number of student who speak only Hindi = (60 - 30) = 30 ∴Number of student who speak Hindi = 30 + 12 = 42

Question 13

The ratio of males and females in a city is 7:8 and the percentage of children among males and females is 25% and 20% respectively.If the number of adult females in the city is 156800, what is the total population?

Accepted Answer

Number of females = 156800 x 100/80 = 196000 ∴ Number of males = 7/8 x 196000 = 171500 Total population = 196000 + 171500 = 367500

Question 14

The ratio of the number of student appearing for examination in the year 1998 in the states A, B and C was 3 : 5 : 6. Next year if the number of students in these states increase by 20%, 10% and 20% respectively, the ratio in states A and C would be…

Accepted Answer

Let the number of students appearing for examination in the year 1998 in the states A, B and C be 3N, 5N,and 6N respectively. According to the question, {(3N x 120)/100} / {(6N x 110)/100} = 1/2 Its true for every N so, The data is inadequate.

Question 15

After spending 40% in machinery, 25% in building,15% in raw material and 5% on furniture. hari lal has a balance of Rs. 1305. The money with him was?

Accepted Answer

Let the Hari Lal was having R rupees in beginning. ∵ R - [40% of R + 25% of R + 15% of R + 5% of R] = 1305 ⇒ R - 85% of R = 1305 ⇒ 15% of R = 1305 ∴ R = (1305 x 100)/15 = 8700

Question 16

In mathematics exam. a student scored 30% marks in the first paper out of a total of 180. How much should he score in second paper out of a total of 150, If he is to get an overall average of at least 50%?

Accepted Answer

∵ 30% of 180 + N% of 150 = 50% of (180 + 150) ⇒ 54 + (N x 150)/100 = 165 ⇒ 3N/2 = 111 ∴ N = (111 x 2) / 3 =74

Question 17

In a examination it is required to get 36% of maximum marks to pass. A student got 113 marks and declared failed by 85 marks. The maximum marks are?

Accepted Answer

∵ 36% of N = (113 + 85) ∴ N = (100 x 198) / 36 = 550

Question 18

From the salary of an officer 10% deducted as house rent,15% of the rest he spends on children's eduction and 10% of the balance, he spends on clothes. After this expenditure he is left with Rs. 1377. His salary is?

Accepted Answer

Suppose that his salary = Rs. 100 House Rent = Rs.10 so, Balance = Rs. 90 Expenditure on education = Rs. (15 x 90) / 100= Rs.13.50 Balance =Rs.76.50 Expenditure on clothes = Rs.(10 x 76.50) / 100 = Rs. 7.65 Balance now = Rs.68.85 If balance is Rs. 68.85, salary =Rs. 100 If balance is Rs. 1377, salary = Rs.(100/68.85) x 1377 = Rs. 2000

Question 19

The price of cooking oil has increased by 25%. The percentage of reduction that a family should effect in the use of cooking oil so as not to increased the expenditure on this account is?

Accepted Answer

Reduction in consumption = { m / (100 + m)} x 100% = (25/125) x 100% = 20%

Question 20

Out of a total 85 children playing badminton or table tannins or both,total number of girl in the group is 70% of boys in the group. The number of boys playing only badminton is 50% of the number of boys and the total number of boys playing badminto…

Accepted Answer

Let the number of boys = x then x + 7x/10 = 85 ⇒ x = 50 ∴ No. of girls = 85 - 50 = 35 (i) Number of boys playing only badminton =50% of boys = 50/100 x 50 = 25 (ii) Number of children playing only table tennis = 40% of total no. of children = 40/100 x 85 = 34 (iii) Total no. of children playing both badminton and table tennis = 12 Hence, number of girls playing only badminton = 85 - (25 + 34 + 12) = 85 - 71 = 14.

Percentage Questions