Question 1

The sum of the number of boys and girls in a school is 150. if the number of boys is x, then the number of girls becomes x% of the total number of students. The number of boys is :

Accepted Answer

We have : x + (x% of 150 )= 150 => x+(x/100)*150] = 150 => 5 2 x = 150 => x = (150*2)/5 = 60

Question 2

In a class of 80 students and 5 teachers, each student got sweets that are 15% of the total number of students and each teacher got sweets that are 25% of the total number of students. How many sweets were there?

Accepted Answer

Total number of sweets = 80 x 15 x 80/100 + 5 x 80 x 25/100 = 960 + 100 = 1060

Question 3

One hour is what percent of a day?

Accepted Answer

A day has 24 hrs => If 24 hrs - 100 Then 1 hr = ? 100/24 = 4.16%

Question 4

The difference between a number and its two-fifth is 510. What is 10% of that number ?

Accepted Answer

Let the number be x. Then, x-(2/5)x = 510 => 3x/5 =510 =>x =[510 * ( 5/3)] =850 10 % 0f 850 = 85.

Question 5

A number is increased by 20% and then decreased by 20%, the final value of the number is ?

Accepted Answer

Here, x = 20 and y = - 20 Therefore, the net % change in value = x + y + x y 100 % = 20 + - 20 + 20 × - 20 100 % or - 4% Since the sign is negative, there is a decrease in value by 4%.

Question 6

In a City, 35% of the population is composed of migrants, 20% of whom are from rural areas. Of the local population, 48% is female while this figure for rural and urban migrants is 30% and 40% respectively. If the total population of the city is 728…

Accepted Answer

324138

Question 7

A shopkeeper’s earning increases by 25% in first year but decreases by 4% in the next and so on. After 5 years his total earnings would be Rs. 72,000. What is his present earning?

Accepted Answer

Let his present earnings be Rs. p ATQ, (125/100) x (96/100) x (125/100) x (96/100) x (125/100) x p = 72000 p = Rs. 40,000.

Question 8

When the price of rice decrease by 10%, a girl could buy 1 kg more for Rs. 270. Then, the original price of the rice per kg is

Accepted Answer

From the given data, When the price of rice is decreased by 10%, the value of Rs. 270 would become 270 x 100/90 = 300 Now, the value 270 becomes 300 And given, the girl could buy 1 kg extra for that value Change in value = 300 - 270 = Rs. 30 Therefore, 1 kg extra rice she can get for Rs. 30 => The original price of rice = Rs. 30/kg. As she gets only 9 kgs for Rs. 270 before 10% discount, now after discount she gets 10 kgs instead of 9 kgs for Rs. 270.

Question 9

An agent, gets a commission of 2.5% on the sales of cloth. If on a certain day, he gets Rs. 12.50 as commission, the cloth sold through him on that day is worth

Accepted Answer

Let the total sale be Rs. x. Then, 2.5%. of x = 12.50 => (25/100 * 1/100 * x) = 125/10 => x = 500.

Question 10

45% of 750 - 25% of 480 = ?

Accepted Answer

Given expression = (45 x 750/100) - (25 x 480/100) = (337.50 - 120) = 217.50

Question 11

How many litres of pure acid are there in 8 litres of a 20% solution ?

Accepted Answer

Quantity of pure acid = 20% of 8 litres = ((20/100)*8) litres = 1.6 litres.

Question 12

56% of 225 + 20% of 150 = ? - 109 Find the value of '?' in the above equation

Accepted Answer

Given 56% of 225 + 20% of 150 = ? - 109 we know that a% of b = b% of a Now, 225% of 56 + 20% of 150 = ? - 109 200% of 56 + 25% of 56 + 20% of 150 = ? - 109 112 + 14 + 30 = ? - 109 ? = 112 + 14 + 30 + 109 ? = 264

Question 13

If P is 140, which is 40% more than Q, then 3/25 of Q is

Accepted Answer

From the given data, P = 140 But it is given that, 40% of Q + Q = 140 = P => Q + [40Q/100] = 140 => [100Q + 40Q]/100 = 140 => 140Q = 140 x 100 => Q = 100 Now, 3/25 of Q = (3/25) x 100 = 3 x 4 = 12 Required 3/25 of Q = 12.

Question 14

A batsman scored 120 runs which included 3 boundaries and 8 sixes. What percent of his total score did he make by running between the wickets ?

Accepted Answer

Number of runs made by running = 120 - (3 x 4 + 8 x 6) = 120 - (60) = 60 Required percentage = [(60/120)*100] % = 50%

Question 15

In an examination, 34% of the students failed in Mathematics and 42% faiied in English. If 20% of the students failed in both the subjects, then the percentage of students who passed in both the subjects was :

Accepted Answer

n (A) = 34, n (B) = 42, n (A ∩ B) = 20. So, n (A U B) = n (A) + n(B) - n(A ∩B) = 34 + 42 - 20 = 56. Percentage failed in either or both the subjects = 56. Hence, percentage passed = (100 - 66)% = 44%.

Question 16

While purchasing one item costing Rs. 400, I had to pay the sales tax at 7% and on another costing Rs. 6400, the sales tax was 9%. What percent of the sales tax I had to pay, taking the two items together on an average ?

Accepted Answer

Total sales tax paid = 7% of Rs, 400 + 9% of Rs. 6400 =Rs. (7/100)*400 + (9/100)*6400 = Rs. (28 + 576) = Rs. 604. Total cost of the items = Rs. (400 + 6400) = Rs. 6800. Required percentage =(604/6800*100) % = 8 15 17 %.

Question 17

Abhinav scores 80% in physics and 66% in chemistry and the maximum marks of both the papers are 100. what percent does he score in maths which is of 200 marks, if he scores 80% marks in all the three subjects:

Accepted Answer

80 100 + 66 100 + x 200 = 320 400 =>x = 174 => 87%

Question 18

If price of rice increased by 25%, so that a man is can able to purchase 5 kg less rice in Rs. 500. Find the original price of rice per kg ?

Accepted Answer

Let the original price of rice be Rs. x Let rice a man can buy for Rs. 500 at rs. x/kg be = R kgs From given data, for Rs. 500 x ---- R kgs (x + 25x/100) ---- (R - 5) kgs => Rx = (R - 5)(x + 25x/100) => Rx = (R - 5)(125x/100) => 100Rx = 125Rx - 625x => R = 25 So at rate of Rs. x/kg, man get 25 kgs for Rs. 500 => x = 500/25 = Rs. 20

Question 19

Solve 30 + (.0825 x 30) + (15% x 30)

Accepted Answer

30 + (.0825 x 30) + (15% x 30) Now => 0.0825 x 30 = 2.475 -----(1) => 15% of 30 = 450/100 = 4.5 -----(2) Hence, from (1) & (2) 30 + (.0825 x 30) + (15% x 30) = 30 + 2.475 + 4.5 30 + (.0825 x 30) + (15% x 30) = 36.975.

Question 20

The price of a cycle is reduced by 25 per cent. The new price is reduced by a further 20 per cent. The two reductions together are equal to a single reduction of

Accepted Answer

Let the original price of the cycle be 100. After the first reduction the price will be 75. This new price is then reduced by 20% = 0.8 x 75 = 60 60 represents a reduction of 40 percent on the original.

Percentage Questions