Question 1

A clock is set right at 5:00 am and loses 16 minutes in every 24 hours. What is the true time when this slow clock indicates 10:00 pm on the 4th day?

Accepted Answer

Introduction / Context: A slow clock shows less indicated time than true. Convert indicated elapsed time to true elapsed using the rate factor for loss. Given Data / Assumptions: Loss: 16 min per 24 h → rate r = indicated/true = (1440 − 16)/1440 = 1424/1440. Set right: 5:00 am (Day 1). Indicated: 10:00 pm on Day 4. Concept / Approach: Indicated elapsed from Day 1 5:00 am to Day 4 10:00 pm = 3 days 17 h = 89 h. True elapsed = 89 * (1440/1424) = 90 h. Step-by-Step Solution: Add 90 h to 5:00 am (Day 1) → Day 4 11:00 pm. Verification / Alternative check: Since the clock is slow, true time should be later than indicated; 11:00 pm is 1 hour later than 10:00 pm, consistent with the computed factor. Why Other Options Are Wrong: 9:00 am/pm and 11:00 am violate direction (they imply earlier time), not later. Common Pitfalls: Using inverse factor (making the time earlier instead of later). Final Answer: 11 : 00 pm

Question 2

If a clock takes 22 seconds to strike 12 times (uniform intervals), how long will it take to strike 6 times?

Accepted Answer

Introduction / Context: For striking clocks, the count of intervals equals (strikes − 1). Time scales with intervals if the interval length is constant. Given Data / Assumptions: 12 strikes → 11 intervals → 22 s total. Concept / Approach: Interval = 22/11 = 2 s. For 6 strikes → 5 intervals. Step-by-Step Solution: Time = 5 * 2 = 10 seconds. Verification / Alternative check: Proportional reasoning is straightforward. Why Other Options Are Wrong: 12 s and 14 s assume wrong interval counts; 9 s ignores uniformity. Common Pitfalls: Using 6 instead of 5 intervals for 6 strikes. Final Answer: 10 seconds

Question 3

March 5, 1999 was a Friday. What day of the week was March 5, 2000?

Accepted Answer

Introduction / Context: From a known weekday, advance one year while accounting for leap years to find the weekday on the same date next year. Given Data / Assumptions: Start: Friday (05-03-1999). Year 2000 is a leap year. Concept / Approach: From Mar 5, 1999 to Mar 5, 2000 includes Feb 29, 2000, so shift = +2 days (common year gives +1; leap year with Feb 29 between dates adds an extra +1). Step-by-Step Solution: Friday + 2 days → Sunday. Verification / Alternative check: Calendar lookup confirms Mar 5, 2000 was Sunday. Why Other Options Are Wrong: Monday/Friday/Tuesday correspond to miscounting leap-day effect. Common Pitfalls: Adding only +1 for a leap year even though Feb 29 lies between the two dates. Final Answer: Sunday

Question 4

India’s first Republic Day was celebrated on January 26, 1950. What was the day of the week on that date?

Accepted Answer

Introduction / Context: Historic weekday identification for 26-01-1950 (first Republic Day of India). We use standard day-of-week calculations or verified references. Given Data / Assumptions: Date: 26-01-1950. Concept / Approach: Apply a day-of-week algorithm (e.g., month codes/century codes) with leap-year handling for 1900s, or verify via authoritative calendar tables. Step-by-Step Solution (sketch): Combine century code (1900s), year code (50), month code (January with leap considerations after 1900), and date 26.Compute modulo 7 to arrive at Thursday. Verification / Alternative check: Public records and calendar archives list 26 January 1950 as Thursday. Why Other Options Are Wrong: They do not match the established weekday for that date. Common Pitfalls: For January/February, leap-year offsets are often mishandled for 1900-series years. Final Answer: Thursday

Question 5

If the day after tomorrow is Sunday, then what day was “tomorrow’s day before yesterday”? (Assume standard consecutive days.)

Accepted Answer

Introduction / Context: This is a verbal logic/calendar question testing careful parsing of relative-day phrases. Given Data / Assumptions: “Day after tomorrow” = Sunday. Concept / Approach: Let today be T. If T + 2 = Sunday, then T = Friday. Step-by-Step Solution: Tomorrow = T + 1 = Saturday.“Tomorrow’s day before yesterday” = (T + 1) − 2 = T − 1 = Thursday. Verification / Alternative check: Enumerate: Thu (T − 1), Fri (T), Sat (T + 1), Sun (T + 2). Works. Why Other Options Are Wrong: Friday/Monday/Tuesday result from offset mistakes (±1 error). Common Pitfalls: Reversing “tomorrow’s day before yesterday” as “day before tomorrow” (which would be today). Final Answer: Thursday

Question 6

A watch gains 3 minutes in every 30 minutes (i.e., runs fast). It is set correctly at 5:00 am. After 6 true hours, what time will this watch show?

Accepted Answer

Introduction / Context: A consistently fast watch accumulates extra indicated minutes. Convert a true-time interval to indicated time by adding the total gain. Given Data / Assumptions: Gain = 3 minutes per 30 minutes of true time. True interval considered = 6 hours = 12 halves of an hour. Concept / Approach: Total gain over 6 hours = 12 * 3 = 36 minutes. Step-by-Step Solution: True 6 hours after 5:00 am → 11:00 am.Indicated = 11:00 am + 36 minutes = 11:36 am. Verification / Alternative check: Rate form: in 60 true minutes, gain = 6 minutes; in 360 minutes, gain = 36; same result. Why Other Options Are Wrong: 10:54 am implies a losing watch; 11:30 or 11:42 are incorrect gains. Common Pitfalls: Multiplying by 6 instead of by 12 half-hours. Final Answer: 11 : 36 am

Question 7

Reaching the place of meeting on Tuesday 15 min before 8:30 h, Anuj found himself half an hour earlier than the man who was 40 min late. What was the scheduled time of the meeting?

Accepted Answer

Anuj reached the place of meeting at 8:15 h, he reached 30 min earlier than the man who was 40 min late, Hence, the scheduled time of the meeting was 8:05 h.

Question 8

A clock buzzes 1 time at 1 O'clock, 2 time at 2 O'clock, 3 times at 3 O'clock and so on. What will be the total number of buzzes in a day?

Accepted Answer

Number of buzzes in a day = 12(12 + 1)/2 x 2 = 156

Question 9

How many times are the hands of a clock is at right angle in a day?

Accepted Answer

In 12 h, they are at a right angles, 22 times. So, in 24 h, they are at right angles, 44 times.

Question 10

How many times do the hands of a clock coincide in a day?

Accepted Answer

From the properties of the clock, we know that hands of a clock coincide once in every hour but between 11 O'clock and 1 O'clock, they coincide only once. Therefore, the hands of a clock coincide 11 time in every 12 h. Hence, they will coincide (11 x 2) = 22 times in 24 h. 89 h of this clock = 90 h of correct clock Therefore, it is clear that in 89 h this clock losses 1 h and hence, the correct time is 11 : 00 pm when this clock shown 10 : 00 pm.

Question 11

How many times do the hands of a clock points towards each other in a day?

Accepted Answer

The hands of a clock point towards each other 11 times in every 12 h (because between 5 and 7, they point towards each other only once at 6 O'clock). Therefore, in a day, the hands points 22 times in all, towards each other.

Question 12

If today is Thursday, what will be the day on 363 days?

Accepted Answer

Here, 363/7 = 51 weeks + 6 days

Question 13

Today is Monday. After 61 days, it will be

Accepted Answer

Each day of the week is repeated after 7 days. So, after 63 days, it will be Monday. After 61 days, it will be Saturday.

Question 14

Today is Wednesday , what will be the day after 84 days?

Accepted Answer

Everyday of the weeks is repeated after 7 days. Hence, it will be Wednesday after 84 days.

Question 15

Today is Thursday. The day after 59 days will be

Accepted Answer

Everyday of the week is repeated after 7 days. Hence, after 56 days, it would be Thursday again and after 59 days, it would be Sunday.

Question 16

Which of the following is not a leap year?

Accepted Answer

The century divisible by 400 is a leap year. The year 707 is not a leap year.

Question 17

If January 1 is a Friday, what is the first day of the month of March in a leap year?

Accepted Answer

Total number of days from January 1 to march 1 = 31 + 29 + 1 = 61 days (February in leap years = 29 days) = 61 ÷ 7 = 8 weeks and 5 odd days So, the fifth day from Friday = Tuesday

Question 18

A bus for Delhi leaves every 30 minutes from a bus stand. An inquiry clerk told a passenger that the bus had already left 10 min ago and next bus will leave at 9 : 35 am. At what time did the inquiry clerk give this information to the passenger?

Accepted Answer

Next bus will leave at 9 : 35 am. So, last bus left at (9 : 35 - 0 : 30) = 9 : 50 am So, inquiry clerk gave the information to the passenger at = (9 : 05 + 0 : 10) = 9 : 15 am So, the next Tuesday will come on the Mrs Susheela's wedding anniversary in 30th September, 2003

Question 19

The day before the day before yesterday is three days after Saturday. What day is it today?

Accepted Answer

Three days after Saturday is Tuesday and Tuesday is a day before a day before yesterday So, yesterday is Tuesday. Hence, today is Friday.

Question 20

Find the angle between minute hand and hour hand at 4 : 20 Am

Accepted Answer

At 4 : 20 A.M. from the formula here P = 4 and Q = 20 so required angle is 11 x 20/2 - 30 x 4 = 110 - 120 = - 10 or ignoring the negative sign the required angle is 10°

Calendar Questions