The perimeters of two squares are 40cm and 32 cm. Find the perimeter of a third square whose area is equal to the difference of the areas of the two squares.

12
24
36
48

Correct Answer: 24

Explanation:

side of first square = 40/4 =10cm

side of second square = 32/4 = 8cm

area of third squre = 10² - 8² = 36 sq cm

side of third square = $36$ = 6 cm

required perimeter = 6*4 = 24cm

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