Frequency-domain conversion: Which formula correctly converts an amplitude ratio (AR) into decibels (dB)?

Difficulty: Easy

Correct Answer: Decibel = 20 log10(AR)

Explanation:


Introduction / Context:
Engineers often express frequency-response magnitudes on a logarithmic scale to simplify multiplication into addition and to align with human perception. The decibel (dB) scale is standard in Bode plots and control/communications. Choosing the correct conversion from amplitude ratio (AR) to decibels is essential for proper gain and margin calculations.


Given Data / Assumptions:

  • Amplitude ratio AR is a non-negative real number representing |G(jω)|.
  • Base-10 logarithms are used for dB in engineering (unless explicitly stated otherwise).
  • We are converting an amplitude (not power) ratio.


Concept / Approach:
By definition for amplitudes, dB = 20 * log10(AR). For power ratios, the coefficient is 10 because power ∝ amplitude^2, so 10 log10(PR) = 20 log10(AR). Using natural logs is possible but then a conversion factor must be included (20/ln(10)). Without that factor, expressions using loge are incorrect for straight substitution.


Step-by-Step Solution:

Start with amplitude ratio AR = |G(jω)|.Convert to dB using dB = 20 * log10(AR).Use this in Bode magnitude plots and gain margin computations.


Verification / Alternative check:
Check a known case: AR = 10 → dB = 20 log10(10) = 20 dB; AR = 0.1 → dB = −20 dB. These match standard results.


Why Other Options Are Wrong:

20 loge(AR): missing the 1/ln(10) conversion; numerically incorrect.20 log10(AR)^0.5: equivalent to 10 log10(AR) (power ratio), not the amplitude ratio definition.20 loge(AR)^0.5: combines natural log with a square-root; also incorrect without conversion.


Common Pitfalls:
Mixing up amplitude vs. power ratio formulas; always use 20 for amplitude and 10 for power, both with log base 10 unless stated otherwise.


Final Answer:
Decibel = 20 log10(AR)

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