Difficulty: Easy
Correct Answer: Reciprocal of amplitude ratio
Explanation:
Introduction / Context:Gain margin quantifies how much the loop gain can increase before a closed-loop system becomes unstable. It is read from Bode plots at the phase-crossover frequency, where the phase equals −180 degrees. Understanding the numerical relationship ensures correct computation and interpretation.
Given Data / Assumptions:
Concept / Approach:By definition, gain margin (GM) = 1/|L(jωpc)| when |L| is expressed as amplitude ratio. In dB, GM(dB) = −20 log10|L(jωpc)|. If |L| is less than one at phase crossover, GM > 1 (or positive in dB), indicating a stable reserve.
Step-by-Step Solution:
Locate ωpc where phase = −180°.Read the magnitude |L| (AR) at ωpc.Compute GM = 1/AR, or in dB: GM(dB) = −20 log10(AR).Verification / Alternative check:Example: if AR = 0.2 at ωpc, then GM = 5 or +14 dB; if AR = 1, GM = 1 (0 dB), indicating marginal stability.
Why Other Options Are Wrong:
Amplitude ratio: this is inverted to obtain GM; not equal to GM.Gains in P or PI controllers are design parameters, not the definition of gain margin.Common Pitfalls:Confusing crossover frequencies: gain margin uses phase crossover; phase margin uses gain crossover (|L| = 1).
Final Answer:Reciprocal of amplitude ratio
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