Stability margins from Bode plots: In frequency-response analysis, the gain margin is numerically equal to which of the following quantities (using amplitude ratio at the phase-crossover frequency)?

Difficulty: Easy

Correct Answer: Reciprocal of amplitude ratio

Explanation:


Introduction / Context:
Gain margin quantifies how much the loop gain can increase before a closed-loop system becomes unstable. It is read from Bode plots at the phase-crossover frequency, where the phase equals −180 degrees. Understanding the numerical relationship ensures correct computation and interpretation.


Given Data / Assumptions:

  • Open-loop transfer function L(jω) = G(jω)H(jω).
  • Phase-crossover frequency ωpc satisfies ∠L(jωpc) = −180°.
  • Amplitude ratio (AR) denotes |L(jω)| at the specified frequency.


Concept / Approach:
By definition, gain margin (GM) = 1/|L(jωpc)| when |L| is expressed as amplitude ratio. In dB, GM(dB) = −20 log10|L(jωpc)|. If |L| is less than one at phase crossover, GM > 1 (or positive in dB), indicating a stable reserve.


Step-by-Step Solution:

Locate ωpc where phase = −180°.Read the magnitude |L| (AR) at ωpc.Compute GM = 1/AR, or in dB: GM(dB) = −20 log10(AR).


Verification / Alternative check:
Example: if AR = 0.2 at ωpc, then GM = 5 or +14 dB; if AR = 1, GM = 1 (0 dB), indicating marginal stability.


Why Other Options Are Wrong:

Amplitude ratio: this is inverted to obtain GM; not equal to GM.Gains in P or PI controllers are design parameters, not the definition of gain margin.


Common Pitfalls:
Confusing crossover frequencies: gain margin uses phase crossover; phase margin uses gain crossover (|L| = 1).


Final Answer:
Reciprocal of amplitude ratio

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