Syllogism validation with set inclusion: if all trees in the park are flowering and some trees are dogwoods, assess the claim 'All dogwoods in the park are flowering trees'

Logical Reasoning Logical Problems Difficulty: Easy
Choose an option
  • A
    True
  • B
    False
  • C
    Uncertain (depends on season)
  • D
    True only for mature dogwoods
  • E
    False unless dogwoods are a majority

Answer

Correct Answer: True

Explanation

Given data

  • All Trees_in_park ⊆ Flowering.
  • Some Trees_in_park ∩ Dogwoods ≠ ∅.

Concept/Approach (why this method)

Universal inclusion: every member of the 'trees in the park' set is flowering; any subclass (e.g., dogwoods in the park) inherits this property.

Step-by-Step deduction1) Let D = {dogwoods in the park}. By premise, D ⊆ Trees_in_park.2) Since Trees_in_park ⊆ Flowering, transitivity gives D ⊆ Flowering.

Verification/Alternative

Venn diagram: place 'Trees' circle fully inside 'Flowering'; 'Dogwoods in park' is a sub-region within 'Trees', hence also inside 'Flowering'.

Common pitfalls

  • Confusing 'some trees are dogwoods' with 'some dogwoods are flowering'—here all park trees are flowering, so all park dogwoods are flowering.

Final AnswerTrue

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