Thiem equation for a confined aquifer (steady radial flow) In a pumping test on a confined aquifer of saturated thickness b, a steady discharge Q is pumped from a well. Two observation wells at radii r1 and r2 from the pumped well show piezometric heads h1 and h2 respectively. According to Thiem, the coefficient of permeability K is obtained from which equation (use natural logarithm)?

Difficulty: Medium

Correct Answer: K = (Q / (2 * π * b)) * ln(r2 / r1) / (h2 - h1)

Explanation:


Introduction / Context:
The Thiem equation is a classical steady-state solution for radial flow toward a pumping well. It allows hydrogeologists to estimate the hydraulic conductivity (permeability K) of an aquifer from discharge and drawdown observations in two observation wells.



Given Data / Assumptions:

  • Confined aquifer of uniform thickness b and homogeneous/isotropic properties.
  • Steady pumping at constant discharge Q.
  • Two observation wells at radii r1 and r2 with observed piezometric heads h1 and h2.
  • Dupuit–Forchheimer assumptions: predominantly horizontal flow, negligible vertical gradients near observation points.


Concept / Approach:
For a confined aquifer under steady radial flow, the head distribution satisfies a logarithmic decline with radius. Integrating Darcy’s law in cylindrical coordinates between r1 and r2 gives a direct relationship among Q, K, b, and the measured heads.



Step-by-Step Solution:

Start with Darcy’s law for radial flow: Q = 2 * π * r * b * K * dh/dr.Separate and integrate: ∫(h1→h2) dh = (Q / (2 * π * b * K)) ∫(r1→r2) (dr / r).This yields h2 - h1 = (Q / (2 * π * b * K)) * ln(r2 / r1).Solve for K: K = (Q / (2 * π * b)) * ln(r2 / r1) / (h2 - h1).


Verification / Alternative check:
Dimension check: Q has L^3/T; denominator 2 * π * b has L; the remaining ratio ln(r2/r1)/(h2 - h1) has 1/L; overall gives L/T as expected for K.



Why Other Options Are Wrong:

  • Option B is for unconfined Thiem (uses h^2), not confined.
  • Option C is the algebraic inverse (K in denominator of Q); it gives 1/K form.
  • Option D omits thickness b and misplaces terms.
  • “All the above” is false because only one equation is correct for the confined case posed.


Common Pitfalls:
Mixing the confined and unconfined forms (h vs h^2), using base-10 log instead of natural log without adjusting constants, and selecting observation wells too close to the pumped well (well losses).



Final Answer:
K = (Q / (2 * π * b)) * ln(r2 / r1) / (h2 - h1)

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