Stefan–Boltzmann law: For an ideal black body, the total emissive power per unit area is directly proportional to which function of absolute temperature?
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AT (first power of absolute temperature)
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BT^2 (square of absolute temperature)
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CT^3 (cube of absolute temperature)
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DT^4 (fourth power of absolute temperature)
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Elog(T) (natural logarithm of absolute temperature)
Answer
Correct Answer: T^4 (fourth power of absolute temperature)
Explanation
Introduction / Context:Thermal radiation from surfaces is central to high-temperature heat transfer. The Stefan–Boltzmann law provides the fundamental relation for the total emissive power of a black body.
Given Data / Assumptions:
- Ideal black body surface (emissivity = 1).
- Absolute temperature T in Kelvin.
- Stefan–Boltzmann constant sigma is a universal constant.
Concept / Approach:The law states: E_b = sigma * T^4 where E_b is the emissive power (W/m^2). The fourth-power dependence means small increases in temperature cause large increases in radiative heat emission.
Step-by-Step Solution:Recognize black body assumption → emissivity = 1.Apply Stefan–Boltzmann equation: E_b proportional to T^4.Conclude the correct functional dependence is the fourth power.
Verification / Alternative check:Compare with gray body: E = epsilon * sigma * T^4; the exponent remains 4; epsilon only scales magnitude.
Why Other Options Are Wrong:
- T, T^2, T^3, log(T): none capture the steep growth rate observed and proven in radiation physics; only T^4 matches experiments and theory.
Common Pitfalls:Confusing the Stefan–Boltzmann law with Wien’s displacement law (which relates peak wavelength and temperature).
Final Answer:T^4 (fourth power of absolute temperature)