Stefan–Boltzmann law: For an ideal black body, the total emissive power per unit area is directly proportional to which function of absolute temperature?

Difficulty: Easy

Correct Answer: T^4 (fourth power of absolute temperature)

Explanation:


Introduction / Context:
Thermal radiation from surfaces is central to high-temperature heat transfer. The Stefan–Boltzmann law provides the fundamental relation for the total emissive power of a black body.



Given Data / Assumptions:

  • Ideal black body surface (emissivity = 1).
  • Absolute temperature T in Kelvin.
  • Stefan–Boltzmann constant sigma is a universal constant.


Concept / Approach:
The law states: E_b = sigma * T^4 where E_b is the emissive power (W/m^2). The fourth-power dependence means small increases in temperature cause large increases in radiative heat emission.



Step-by-Step Solution:
Recognize black body assumption → emissivity = 1.Apply Stefan–Boltzmann equation: E_b proportional to T^4.Conclude the correct functional dependence is the fourth power.



Verification / Alternative check:
Compare with gray body: E = epsilon * sigma * T^4; the exponent remains 4; epsilon only scales magnitude.



Why Other Options Are Wrong:

  • T, T^2, T^3, log(T): none capture the steep growth rate observed and proven in radiation physics; only T^4 matches experiments and theory.


Common Pitfalls:
Confusing the Stefan–Boltzmann law with Wien’s displacement law (which relates peak wavelength and temperature).



Final Answer:
T^4 (fourth power of absolute temperature)

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