Rankine's empirical design: according to Rankine's formula, what is the minimum depth D of foundation embedment in terms of soil unit weight γ, allowable bearing pressure q (at foundation level), and soil friction angle φ?
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AD = (q / γ) * ((1 - sin φ) / (1 + sin φ))^2
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BD = (2 q / γ) * ((1 - sin φ) / (1 + sin φ))
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CD = (q / γ) * ((1 + sin φ) / (1 - sin φ))^2
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DD = (q / γ) * tan^2(45° + φ/2)
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ED = (q / γ) * tan^2(45° - φ/2)
Answer
Correct Answer: D = (q / γ) * ((1 - sin φ) / (1 + sin φ))^2
Explanation
Introduction / Context:Rankine's depth of foundation formula provides a minimum embedment to prevent shear failure and ensure the overburden confining pressure mobilizes adequate passive resistance. It relates the foundation depth to soil strength parameters in a simple closed form widely used for preliminary sizing.
Given Data / Assumptions:
- Soil unit weight = γ (kN/m^3).
- Allowable bearing pressure at foundation level = q (kN/m^2).
- Effective stress friction angle = φ (degrees).
- Groundwater effects and cohesion are neglected for simplicity.
Concept / Approach:Rankine's active earth pressure coefficient K_a = ((1 − sin φ) / (1 + sin φ))^2. The classic embedment relation may be written as D = (q / (γ K_a)), which rearranges to D = (q / γ) * ((1 − sin φ) / (1 + sin φ))^2. This ensures that vertical overburden at the base provides the confining stress consistent with allowable pressure.
Step-by-Step Solution:Compute K_a = ((1 − sin φ) / (1 + sin φ))^2.Use D = (q / (γ K_a)).Substitute K_a: D = (q / γ) * ((1 − sin φ) / (1 + sin φ))^2.Thus, option (a) matches Rankine's expression.
Verification / Alternative check:For φ = 0°, K_a = 1, giving D = q / γ, which is dimensionally consistent and physically reasonable for purely frictionless soil in this simplified context.
Why Other Options Are Wrong:
- (b) Linear (not squared) ratio; does not reflect Rankine's K_a.
- (c) Inverts the ratio, yielding unrealistic shallow/negative depths.
- (d) and (e) use tan(45° ± φ/2) forms without the square; not Rankine's embedment formula.
Common Pitfalls:Confusing K_a (active) with K_p (passive); omitting the square on ((1 − sin φ)/(1 + sin φ)).
Final Answer:D = (q / γ) * ((1 - sin φ) / (1 + sin φ))^2