Difficulty: Easy
Correct Answer: 5
Explanation:
Introduction / Context:Series connecting SCRs requires voltage derating to accommodate tolerances, temperature, and transient imbalance. This calculation finds the minimum number of devices for a specified DC bus.
Given Data / Assumptions:
Concept / Approach:With derating, allowable steady blocking voltage per SCR becomes V_use = 0.75 * V_Rated. The required count is N ≥ V_total / V_use, rounded up to the next integer.
Step-by-Step Solution:
Compute usable per SCR: V_use = 0.75 * 800 = 600 V.Compute count: N = 3000 / 600 = 5 exactly.Therefore, 5 SCRs in series meet the derated requirement.Verification / Alternative check:
Total derated withstand = 5 * 600 = 3000 V → matches bus voltage (ignoring transients; equalizing networks still recommended).Why Other Options Are Wrong:
4 devices give only 2400 V derated; 6 or more are conservative but not minimal; 8/7 oversize unnecessarily.Common Pitfalls:
Forgetting to derate; confusing AC peak vs DC; not rounding up for non-integer results.Final Answer:
5
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