A DC chopper applies a constant input voltage V to a resistive load for a fraction a (duty cycle) of each period and 0 for the remainder. What is the RMS value of the output voltage across the load?

Introduction / Context:Pulse-width-modulated (PWM) choppers feed a resistive load with a rectangular waveform: V during on-time and 0 during off-time. While the average output is a*V, the RMS value is different and is important for heating and true power calculations in resistive loads.

Given Data / Assumptions:

• Input DC = V (constant).
• Duty cycle = a (0 < a ≤ 1).
• Load is purely resistive; ripple current follows voltage instantly.

Concept / Approach:

RMS value is defined as sqrt( (1/T) * ∫ v^2(t) dt ). For a two-level waveform (V for aT, 0 for (1−a)T), square the levels, integrate over the period, and take the square root. This gives a simple closed form that differs from the average aV.

Step-by-Step Solution:

Verification / Alternative check:

Check limits: a → 1 gives V_rms → V (continuous DC), a → 0 gives V_rms → 0, both consistent.

Why Other Options Are Wrong:

• aV: average value, not RMS.
• a^2V, V/√a, V/a: incorrect scaling; fail limit checks at a → 0 or a → 1.

Common Pitfalls:

• Confusing RMS with average (both relevant but distinct).
• Forgetting to square before integrating for RMS.

Final Answer:

V * sqrt(a)