Difficulty: Easy
Correct Answer: 3 minutes 15 seconds
Explanation:
Introduction / Context:
This is a standard race problem where a distance lead is also given as a time lead. We use B’s speed deduced from “25 m in 5 s” and then compute A’s finish time.
Given Data / Assumptions:
Concept / Approach:
When A finishes, B is at 975 m. The shared race time equals the time B takes to cover 975 m at B’s computed speed.
Step-by-Step Solution:
Verification / Alternative check:
In 195 s, B would need 25 m more (5 s) to finish; consistent with the statement.
Why Other Options Are Wrong:
Other times do not produce a 25 m (5 s) shortfall for B at A’s finish.
Common Pitfalls:
Using 1000 m for B instead of 975 m for the common time reference.
Final Answer:
3 minutes 15 seconds
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