Billiards handicaps transitivity: A gives B 6 in 50 and A gives C 13 in 65. In a game of 55, how many points can B give C?

Difficulty: Medium

Correct Answer: 5

Explanation:

Introduction / Context:We use proportional scoring in equal time. From A:B and A:C ratios we infer B:C and then scale to a 55-point game.

Given Data / Assumptions:

  • A gives B 6 in 50 ⇒ (A:B) = 50:44 = 25:22
  • A gives C 13 in 65 ⇒ (A:C) = 65:52 = 5:4
  • Game size in query = 55 points

Concept / Approach:Compute B:C = (A:C)/(A:B). Then, when B scores 55, compute C’s score and find the points B can give C.

Step-by-Step Solution:

B:C = (5/4) / (25/22) = (5/4)*(22/25) = 11/10If B scores 55 ⇒ C = 55*(10/11) = 50So B can give C = 55 − 50 = 5 points

Verification / Alternative check:Scaling either ratio to a common A-score yields the same B:C relation of 11:10.

Why Other Options Are Wrong:They contradict the deduced B:C = 11:10.

Common Pitfalls:Subtracting handicaps instead of converting them into proportional scoring rates.

Final Answer:5

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