Billiards handicaps transitivity: A gives B 6 in 50 and A gives C 13 in 65. In a game of 55, how many points can B give C?

Difficulty: Medium

Correct Answer: 5

Explanation:


Introduction / Context:
We use proportional scoring in equal time. From A:B and A:C ratios we infer B:C and then scale to a 55-point game.


Given Data / Assumptions:

  • A gives B 6 in 50 ⇒ (A:B) = 50:44 = 25:22
  • A gives C 13 in 65 ⇒ (A:C) = 65:52 = 5:4
  • Game size in query = 55 points


Concept / Approach:
Compute B:C = (A:C)/(A:B). Then, when B scores 55, compute C’s score and find the points B can give C.


Step-by-Step Solution:

B:C = (5/4) / (25/22) = (5/4)*(22/25) = 11/10If B scores 55 ⇒ C = 55*(10/11) = 50So B can give C = 55 − 50 = 5 points


Verification / Alternative check:
Scaling either ratio to a common A-score yields the same B:C relation of 11:10.


Why Other Options Are Wrong:
They contradict the deduced B:C = 11:10.


Common Pitfalls:
Subtracting handicaps instead of converting them into proportional scoring rates.


Final Answer:
5

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