Three friends X, Y, and Z dine together. Z’s meal costs 20% more than Y’s meal, and X’s meal costs 5/6 as much as Z’s meal. If Y pays ₹100, find the total amount paid by all three combined.

Introduction / Context:
This is a percentage-and-ratio chaining problem. You are given relative costs between X, Y, and Z, plus the actual rupee value for Y. Converting the relative statements into multipliers allows quick computation of Z and X, and then summing yields the total bill.

Given Data / Assumptions:

• Y pays ₹100.
• Z is 20% more than Y → Z = 1.2 * Y.
• X is 5/6 of Z → X = (5/6) * Z.
• Total = X + Y + Z.

Concept / Approach:
Work stepwise from the known amount for Y. First, compute Z using the 20% markup. Next, compute X using the 5/6 factor relative to Z. Finally, add X, Y, and Z. Ensure rounding is not needed since all values are exact integers here.

Step-by-Step Solution:

Verification / Alternative check:
Reverse-check percentages: Z is 20% more than 100 (indeed 120). X is 5/6 of 120 (indeed 100). The arithmetic is consistent and exact.

Why Other Options Are Wrong:
₹285, ₹300, and ₹335 do not match the chained percentage relations. Hence the only correct choice is the catch-all “None of these,” since the correct total is ₹320.

Common Pitfalls:
Applying 5/6 to Y instead of Z, or compounding the 20% incorrectly (e.g., adding 20 and 5/6 as if they were on the same base).

Final Answer:
None of these