Difficulty: Easy
Correct Answer: 178
Explanation:
Introduction / Context:
Equally spaced placements along a segment are a classic “inclusive endpoints” counting problem. When the spacing is d along a segment of length L, the number of points on one side is (L / d) + 1, provided trees are placed at both ends. Since there are two sides of the road, double the per-side count for the total.
Given Data / Assumptions:
Concept / Approach:
For one side, with trees at both endpoints, the count is N_side = (L / d) + 1. Then total trees = 2 * N_side, because the same pattern is repeated on the other side. The key is not to forget the extra “+1” that arises from including both endpoints.
Step-by-Step Solution:
Verification / Alternative check:
Visualize marks every 20 m from 0 to 1760 on one side: positions 0, 20, …, 1760 (inclusive). Counting by step size confirms 89 positions per side, validating the formula.
Why Other Options Are Wrong:
176 ignores one of the endpoints across both sides. 180 assumes an extra interval or double-counts. 174 and 172 are undercounts due to missing endpoints or misapplied spacing.
Common Pitfalls:
Using only L / d without adding 1, or forgetting to multiply by 2 for both sides of the road.
Final Answer:
178
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