$x, y, z, u$ are real numbers such that $x : y = y : z = z : u$ and $x : u = 64 : 27$. The value of $x : z$ is
Aptitude
Ratio and Proportion
Difficulty: Medium
Choose an option
-
A$64 : 27$
-
B$16 : 9$
-
C$4 : 3$
-
D$3 : 4$
Answer
Correct Answer: $16 : 9$
Explanation
### Concept & Continued Proportion Multiplication
When variables are in a continued proportion (e.g., $\frac{x}{y} = \frac{y}{z} = \frac{z}{u} = k$), multiplying consecutive ratios together will eliminate intermediate variables and yield a relationship between the outer variables expressed as a power of the constant $k$.
### Step-by-Step Solution
- **Given:** $\frac{x}{y} = \frac{y}{z} = \frac{z}{u} = k$ (where $k$ is a constant ratio).
- **Relate Extremes:** Multiply the three individual ratios to find $\frac{x}{u}$.
$\frac{x}{u} = \left(\frac{x}{y}\right) \times \left(\frac{y}{z}\right) \times \left(\frac{z}{u}\right)$
$\frac{x}{u} = k \times k \times k = k^3$
- **Solve for k:** We are given $\frac{x}{u} = \frac{64}{27}$.
$k^3 = \frac{64}{27}$
Taking the cube root of both sides: $k = \sqrt[3]{\frac{64}{27}} = \frac{4}{3}$.
- **Find Target Ratio:** We need to find $x : z$, which is $\frac{x}{z}$.
Multiply the first two ratios: $\frac{x}{z} = \left(\frac{x}{y}\right) \times \left(\frac{y}{z}\right)$
$\frac{x}{z} = k \times k = k^2$
- **Calculate Final Value:**
$k^2 = \left(\frac{4}{3}\right)^2 = \frac{16}{9}$.
- **Result:** $x : z = 16 : 9$.
### Exam Strategy & Shortcut
Recognize that moving from $x$ to $u$ involves $3$ steps ($x \to y$, $y \to z$, $z \to u$), so the ratio $x/u$ is the base ratio cubed. Thus, the base ratio is the cube root of $64/27$, which is $4/3$. Moving from $x$ to $z$ involves $2$ steps, so we square the base ratio: $(4/3)^2 = 16/9$.
### Common Pitfall
A common pitfall is stopping after finding the base ratio $k = 4/3$ and selecting that as the answer, forgetting that the question specifically asks for $x : z$, which corresponds to $k^2$.
### Final Answer
Therefore, the correct answer is **$16 : 9$**.