In this verbal reasoning question, the base word REASONABLE is given. From the following alternative words, choose the single word that cannot be formed by rearranging and using the letters of REASONABLE, without adding any new letter and without using any letter more times than it appears in the given word.

Introduction / Context:
This verbal reasoning question checks whether you can carefully track letter counts inside a given word and decide which option word cannot be formed from those letters. Such word formation problems are common in many competitive exams because they test observation, accuracy, and attention to detail rather than vocabulary alone.

Given Data / Assumptions:

• The base word is REASONABLE.
• Each option word must be formed only from the letters of REASONABLE.
• No new letter can be introduced.
• No letter can be used more times than it appears in REASONABLE.
• We assume normal English spellings for all words.

Concept / Approach:
The standard approach in such questions is to write down the frequency of each letter in the base word and then compare that frequency with each option. If any option needs a letter that is missing, or needs some letter more times than it appears in the base word, that option cannot be formed. All other options are considered possible formations.

Step-by-Step Solution:
Step 1: Write the base word clearly as REASONABLE. Step 2: Count the letters in REASONABLE. We get: R = 1, E = 2, A = 2, S = 1, O = 1, N = 1, B = 1, L = 1. Step 3: Check EASE. Letters needed are E, A, S, E. That is E = 2, A = 1, S = 1. All of these can be supplied from REASONABLE, so EASE can be formed. Step 4: Check NOBLE. Letters needed are N, O, B, L, E. That is N = 1, O = 1, B = 1, L = 1, E = 1. All are available within the counts of REASONABLE. So NOBLE can be formed. Step 5: Check SEASON. Letters needed are S, E, A, S, O, N. That is S = 2, E = 2, A = 1, O = 1, N = 1. The base word REASONABLE has only S = 1. The demand S = 2 is greater than the supply, so SEASON cannot be formed. Step 6: Check SOLAR. Letters needed are S, O, L, A, R. That is S = 1, O = 1, L = 1, A = 1, R = 1, which are all available. So SOLAR can be formed. Step 7: Check ALONE. Letters needed are A, L, O, N, E. Each of these letters appears at least once in REASONABLE, and the required counts do not exceed the available counts, so ALONE can be formed.

Verification / Alternative check:
An alternative quick check is to focus on the option that seems to repeat some letter noticeably. SEASON clearly repeats S. When you recall that REASONABLE contains only one S, you can immediately conclude that SEASON is impossible, while the other options do not overload any letter beyond its available count. This cross check supports the detailed counting method.

Why Other Options Are Wrong:
EASE uses two E letters, one A, and one S. All of these are present in sufficient number in REASONABLE, so EASE is a valid formation. NOBLE uses N, O, B, L, and E. Each of these letters appears at least once in the base word, and no letter is overused, so NOBLE can be formed. SOLAR uses S, O, L, A, and R. All required letters occur in REASONABLE in at least the needed counts, so SOLAR is also possible. ALONE uses A, L, O, N, and E. Again, each letter is present in REASONABLE in enough quantity, so ALONE can be formed.

Common Pitfalls:
Candidates often only check whether the letters appear at least once and forget to verify the number of times each letter is repeated. In this question, SEASON looks similar to the base word REASONABLE and can trick a hurried reader. Another common mistake is miscounting the letters in the base word or skipping one of the options due to time pressure. Writing down exact counts for each letter helps avoid these errors.

Final Answer:
The only option that requires a second S, which is not available in the base word REASONABLE, is SEASON. Therefore, SEASON is the word that cannot be formed.