Heights — Who among six (Geetha, Shipa, Deepa, Meeta, Sunita, Sadhana) is the tallest? Base facts: Geetha > Shipa; Deepa > Meeta. Statements: I. Sadhana > Sunita. II. Sadhana > Shipa and Meeta and Deepa.

Difficulty: Medium

Correct Answer: Both Statements I and II together are not sufficient.

Explanation:

Introduction / Context:Determine the tallest using partial orderings among six people. DS checks whether a unique maximal element is forced.

Given Data / Assumptions:

  • Base: Geetha > Shipa; Deepa > Meeta.
  • I: Sadhana > Sunita.
  • II: Sadhana > Shipa, Meeta, Deepa.

Concept / Approach:Consolidate known relations and see whether anyone is shown to dominate all others.

Step-by-Step Solution:

From II: Sadhana is taller than Shipa, Meeta, and Deepa. From base, Geetha > Shipa (but no relation between Geetha and Sadhana).I only adds Sadhana > Sunita. After combining I+II+base, we still lack a comparison between Sadhana and Geetha.Thus, either Sadhana is tallest (if Sadhana > Geetha) or Geetha is tallest (if Geetha > Sadhana). Both possibilities satisfy all statements.

Verification / Alternative check:Construct models: (1) Sadhana > Geetha > Deepa > Meeta > Shipa > Sunita; (2) Geetha > Sadhana > Deepa > Meeta > Shipa > Sunita. Both are consistent.

Why Other Options Are Wrong:

  • A/B/C/E: No single statement or their combination determines Sadhana vs Geetha.

Common Pitfalls:Assuming transitive links that are not stated (e.g., inferring Geetha > Deepa without basis).

Final Answer:D — Together not sufficient (tallest could be Sadhana or Geetha).

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