Difficulty: Hard
Correct Answer: Both Statements I and II together are not sufficient.
Explanation:
Introduction / Context:We need the person who is lighter than only the heaviest (rank 2 by weight). Partial inequalities are given.
Given Data / Assumptions:
Concept / Approach:Combine inequalities; check if any person is forced to be second heaviest.
Step-by-Step Solution:
From II: There exists some X with X > J > W > P. From I: P > M, T. K remains unconstrained.Second-heaviest candidate could be J (if only X > J and all others < J), but K might also exceed J because we lack K's relation; in that case, second-heaviest could be K or even X depending on structure.Therefore, no unique identification is possible.Verification / Alternative check:Construct consistent orders where the second heaviest differs (e.g., Case A: X > J > W > P > K > M > T → second = J; Case B: X > K > J > W ... → second = K).
Why Other Options Are Wrong:
Common Pitfalls:Assuming transitivity to absent elements; overlooking that 'J not heaviest' does not place J relative to K.
Final Answer:D — Together not sufficient.
Discussion & Comments