Weights — Among M, P, K, J, T, W, who is lighter than only the heaviest (i.e., second heaviest)? Statements: I. P is heavier than M and T. II. W is heavier than P but lighter than J, and J is not the heaviest.

Difficulty: Hard

Correct Answer: Both Statements I and II together are not sufficient.

Explanation:


Introduction / Context:
We need the person who is lighter than only the heaviest (rank 2 by weight). Partial inequalities are given.


Given Data / Assumptions:

  • I: P > M and P > T.
  • II: J is above W (J > W) and W > P; additionally, J is not the heaviest, meaning someone else is heavier than J.
  • No relations given for K against others.


Concept / Approach:
Combine inequalities; check if any person is forced to be second heaviest.


Step-by-Step Solution:

From II: There exists some X with X > J > W > P. From I: P > M, T. K remains unconstrained.Second-heaviest candidate could be J (if only X > J and all others < J), but K might also exceed J because we lack K's relation; in that case, second-heaviest could be K or even X depending on structure.Therefore, no unique identification is possible.


Verification / Alternative check:
Construct consistent orders where the second heaviest differs (e.g., Case A: X > J > W > P > K > M > T → second = J; Case B: X > K > J > W ... → second = K).


Why Other Options Are Wrong:

  • A/B/C/E: Insufficient constraints; both statements together still leave K and the unknown heaviest free.


Common Pitfalls:
Assuming transitivity to absent elements; overlooking that 'J not heaviest' does not place J relative to K.


Final Answer:
D — Together not sufficient.

More Questions from Data Sufficiency

Discussion & Comments

No comments yet. Be the first to comment!
Join Discussion