Difficulty: Easy
Correct Answer: B-DNA
Explanation:
Introduction / Context:DNA can adopt multiple helical conformations depending on hydration, sequence, and ionic conditions. The historically famous Watson–Crick structure corresponds to a particular form predominant in vivo.
Given Data / Assumptions:
Concept / Approach:B-DNA is the right-handed helix with about 10 base pairs per turn, wide major groove and narrow minor groove, matching the Watson–Crick model. A-DNA is a more compact right-handed form favored in lower hydration; Z-DNA is a left-handed helix occurring transiently in certain GC-rich sequences under high salt or negative supercoiling.
Step-by-Step Solution:
1) Identify the structure historically described by Watson and Crick.2) Compare helical parameters of A, B, and Z forms.3) Select B-DNA as the standard cellular conformation.Verification / Alternative check:X-ray fiber diffraction and crystallography support B-form parameters under physiological hydration. Biochemical footprinting also aligns with B-DNA groove geometry for protein binding.
Why Other Options Are Wrong:
Common Pitfalls:Assuming any right-handed helix equals the classical form, or conflating A-DNA conditions with in vivo chromosomal DNA.
Final Answer:B-DNA.
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