Difficulty: Easy
Correct Answer: Catalase-positive, oxidase-negative, ferment glucose, reduce nitrate to nitrite
Explanation:
Introduction / Context:
At the bench, a quick biochemical profile helps place an unknown Gram-negative rod within Enterobacteriaceae versus other families. A reliable quartet of reactions characterizes most members and guides further identification.
Given Data / Assumptions:
Concept / Approach:
Enterobacteriaceae are facultative anaerobes that generally produce catalase, lack cytochrome c oxidase (oxidase-negative), ferment glucose (acid with or without gas), and reduce nitrate to nitrite via nitrate reductase. These features, taken together, help distinguish them from oxidase-positive non-fermenters (e.g., Pseudomonas) or from organisms that do not reduce nitrate.
Step-by-Step Solution:
Consider catalase: usually positive in Enterobacteriaceae.
Consider oxidase: characteristically negative, separating from many non-enteric rods.
Consider glucose: fermentation is typical across the family.
Consider nitrate: reduction to nitrite is commonly observed.
Select the option that includes all four correct properties together.
Verification / Alternative check:
Textbook identification matrices list this quartet as the starting point for Enterobacteriaceae workups before proceeding to IMViC, TSI slants, urease, and decarboxylases.
Why Other Options Are Wrong:
Common Pitfalls:
Equating lactose fermentation with family membership; lactose is variable, whereas glucose fermentation and oxidase negativity are more reliable family markers.
Final Answer:
Catalase-positive, oxidase-negative, ferment glucose, reduce nitrate to nitrite.
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