Difficulty: Easy
Correct Answer: Diameter increases and length increases
Explanation:
Introduction / Context:
A thin-walled cylinder (pressure vessel) subjected to internal pressure develops circumferential (hoop) and longitudinal stresses. These stresses cause elastic strains that change the vessel dimensions—important for design and safety checks.
Given Data / Assumptions:
Concept / Approach:
Hoop stress sigma_h = p * D / (2 * t) and longitudinal stress sigma_l = p * D / (4 * t). Both are tensile. Tensile strain circumferentially increases diameter; tensile strain longitudinally increases length. Poisson effects exist but the net effect under internal pressure is expansion in both directions for thin cylinders.
Step-by-Step Solution:
Verification / Alternative check:
Experimental observations on thin tubes under pressure exhibit increased diameter and gauge length. Thick-cylinder effects are negligible in thin-wall assumption.
Why Other Options Are Wrong:
Any option indicating decrease in diameter or length contradicts tensile stress-induced expansion under internal pressure.
Common Pitfalls:
Mixing up sign conventions or thinking Poisson contraction can outweigh direct tensile strain; in thin shells under typical pressures, direct tensile strains dominate.
Final Answer:
Diameter increases and length increases
Discussion & Comments